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scoray [572]
3 years ago
7

Please help on this one

Physics
1 answer:
Airida [17]3 years ago
6 0

The answer for this would be "B".

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In this situation, the force is the force of gravity acting on the satellite. This force always points towards the centre of the trajectory, so it is always perpendicular to the direction of motion of the satellite (since the orbit is circular), so \theta=90^{\circ} and cos \theta =0. Therefore, the work done by gravity is also zero.

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