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ivolga24 [154]
3 years ago
7

Viewing behavioral disorders as resulting from disturbances of the nervous syste is the idea that underlies the __________ persp

ective.
neuroscience/biological

cognitive

behavioral

psychodynamic
Physics
2 answers:
Ray Of Light [21]3 years ago
8 0
Its the first one


Hope this helps :)

Hatshy [7]3 years ago
4 0
<span>1. Which observation supported Wegener’s theory of continental drift? Different continents had different rock types. Identical fossils were found on continents that were far apart. Each continent had mountain ranges. The earth’s rotation could provide enough force to move the continents apart. 2. Which feature do you usually see when tectonic plates move apart? ( volcanoes earthquakes mountains new ocean ridges and seafloor 3. What happens in a convection cell? Cold, dense material sinks while hot, less dense material rises. Cold, dense material moves horizontally, while hot, less dense material moves vertically. Hot, less dense material moves horizontally, while cold, dense material moves vertically. Hot, less dense material sinks while cold, dense material rises. 4. In the diagram of the earth’s interior, which part causes the diffraction of P waves made by earthquakes? A B C D. 5. In the diagram of the earth's interior, where does the material that forms volcanoes originate? C A D B 6. In the diagram of the earth’s interior, which part is the densest? C B D A. 7. The sides of a composite-cone volcano are interrupted by which feature? fumaroles craters calderas conduits 8. Which material erupted from volcanoes is important in acid rain? ash carbon dioxide carbon monoxide sulfur dioxide 9. What type of volcano is found along a convergent boundary? rift composite cone shield fissure 10. You have a geological site associated with earthquake activity and a mountain range. You look offshore, but do not find any trenches. What type of boundary are you dealing with? continental-continental convergent boundary divergent boundary undersea oceanic-oceanic convergent boundary oceanic-continental convergent boundary 11. The S-P interval of seismic waves recorded at a seismometer is 8 minutes. Approximately how far away is the earthquake’s epicenter from the seismometer? [equation: (S-P interval) = 0.00146 (distance to epicenter)] 8 km 550 km 5,500 km less than 1 km 12. What kind of plate boundary forms a mountain rainge and a deep ocean trench like the Andes Mountain Range and Peru-Chile trench? divergent plate boundaries oceanic-continental convergence continental-continental convergence transform plate boundaries 13. What is the illustration an example of? hot spot continental-continental convergence boundary oceanic-continental convergence boundary oceanic-oceanic convergence boundary 14. What is the illustration an example of? oceanic-oceanic convergence boundary continental-continental convergence boundary divergent boundary transform boundary. 15. In the illustration, which site is an example of a hot-spot volcano? A B C D 16. In the illustration, which site is an oceanic spreading center? A B C D. 17. In the illustration, which site indicates a fault? D C B A 18. In the illustration, at which site would you expect to find basaltic magma eruptions without volcanoes? A B C D 19. Which of the following features was not created by subduction? Japan Mariana Trench Alps Andes. 20. Paleomagnetic evidence confirms which of the following? seafloor spreading hot spots subduction earthquakes</span>
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What is true of both gravity and magnetism?
stira [4]

Explanation:

I want to say option B - Both forces can act without objects touching.

5 0
3 years ago
You need to repair a gate on the farm. The gate weighs 100 kg and pivots as indicated. A small diagonal bar supports the gate an
tekilochka [14]

Answer:

The force is  F = 3920 \ N

Explanation:

The diagram for this question is shown on the first uploaded image

   From the question we are told that

          The weight of the gate is G  =  100\  kg

 

The vertical component of F is  F_y =  F\ sin  \theta

   From the diagram , taking moment about the pivot we have  

                W_g  * 2 - F_y  * 1 =  0

Where W_g  is the weight of the gate evaluated as

             W_g  =  m_g * g =  100 * 9.8 =  980 \ N

=>        980 * 2 - Fsin(30)  * 1 =  0

=>         F = \frac{1960}{sin(30)}

=>      F = 3920 \ N

7 0
4 years ago
What is the momentum of a .005kg bumble bee that is traveling at a velocity of 3.0m/s?
stiks02 [169]

p=mv

p=0.005kg×3.0m/s

p= 0.015kgm/s

4 0
3 years ago
Acar accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is
s2008m [1.1K]

To understand this question, you need to understand the concept of acceleration first. Have you ever been in a car and noticed that it was getting faster and faster? That "speeding up" of the car is known as acceleration! Acceleration is essentially the rate at which you speed up.

Okay, so we now know what acceleration is. What are its units? The unit of acceleration is the change in velocity over a period of time: \frac{∆v}{t}

If you haven't learned about velocity yet, just think about it as speed for now. The funny-looking triangle, ∆, is a symbol for "the change of." For example, if I started walking at 3 \frac{feet}{second} then sped up to 5 \frac{feet}{second}, then the change in my speed would be 2 \frac{feet}{second}, because I started walking 2 \frac{feet}{second} faster!

Okay, enough with all the explanations. Hopefully, you understand the units now. Let's take a look at the question. A car accelerates from 4 \frac{meters}{second} to 16 \frac{meters}{second}  in 4 seconds. What would the acceleration be? Let's set up an equation:

a = \frac{∆v}{t}

a is the acceleration, ∆v is the change in velocity, and t is the time elapsed.

Now, let's plug in our values! ∆v is the change in velocity, and to find that we simply have to subtract 16 \frac{meters}{second} by 4 \frac{meters}{second}. That makes sense, right? Back to the equation.

a = \frac{∆v}{t}
a = \frac{16-4}{4}

(16 - 4 is the change in velocity, and 4 is the number of seconds the car was accelerating)

a = \frac{12}{4}

a = 3 (\frac{meters}{second^{2}})

We have our answer! The car's acceleration is 3 meters per second^{2}.

(You might be thinking: Wait. Meters per second squared? The reason for that is because acceleration is the rate at which the speed increases! That makes the unit \frac{\frac{meters}{second}}{second}, which can be simplified down to \frac{meters}{second^{2} })

Let me know if you need clarification on anything I explained here!
- breezyツ

6 0
3 years ago
An astronaut inside a spacecraft, which protects her from harmful radiation, is orbiting a black hole at a distance of 120 km fr
mestny [16]

An astronaut inside a spacecraft, which protects her from harmful radiation, is orbiting a black hole at a distance of 120 km from its center. The black hole is 5.00 times the mass of the sun and has a Schwarzschild radius of 15.0 km. The astronaut is positioned inside the spaceship such that one of her 0.030 kg ears is 6.0 cm farther from the black hole than the center of mass of the spacecraft and the other ear is 6.0 cm closer.

What is the tension between her ears?

Would the astronaut find it difficult to keep from being torn apart by the gravitational forces?

Answer:

The tension between the ears = 2.07 KN

The astronaut will find it difficult to keep and will eventually be in trouble because the tension is now greater compared to the tension in the human tissues.

Explanation:

Given that:

Orbital radius of the spacecraft (R) = 120 Km = 120 × 10³ m

Mass of the black hole (m) = 5 \ * (M \ _{sun})

where : M_{sun} = 1.99*10^{33} \ kg

Then; we have:

 m = 5*(1.99*10^{30} \ kg ) \\ = 9.95*10^{30} kg

Schwarzchild radius of the black hole

r - 15.0 km

Mass of each ear m_{ear} = 0.030 \ kg

Farther distance between one ear and the black hole (d) = 6.0 cm

= 0.06 m

Closer distance between the other ear and the black home is (d) 6.0 cm

= 0.6 cm

NOW, If we assume that the tension force should be T; then definitely the two ears will posses the same angular velocity .

The net force on the ear closer to the black hole will be:

\frac{GMm_{ear} }{(R-d)}- T = m_{ear} (R -  d) \omega^2

\frac{GMm_{ear} }{(R-d)^2}- \frac{T}{(R-d)} = m_{ear} \omega^2 \ ----> \ (1)

The net force on the ear farther to the black hole is :

\frac{GMm_{ear} }{(R+d)}- T = m_{ear} (R +  d) \omega^2

\frac{GMm_{ear} }{(R+d)^2}- \frac{T}{(R+d)} = m_{ear} \omega^2 \ ----> \ (2)

Equating equation (1) and (2) & therefore making (T) the subject of the formula; we have:

T = \frac{3GMm_{ear}d}{R^3}

T = \frac{3(6.67*10^{-11}N.m^2/kg^2)(1.95*10^{30}kg)(0.03kg)(0.06m)}{(120*10^3m)^3}

T = 2073.9 N\\T = 2.07 KN

The tension between the ears = 2.07 KN

The astronaut will find it difficult to keep and will eventually be in trouble because the tension is now greater compared to the tension in the human tissues.

3 0
4 years ago
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