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2 years ago

Which one of the following is not matches the organelle with its function

Chemistry

1 answer:

kolbaska11 [484]2 years ago

4 0

Answer:

rip there isnt a photo

Explanation:

i do know a lot about cells tho lol

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Is a burning log an exothermic or endothermic event if the log is the system?

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It would be endothermic because the log is in the system.

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2 years ago

What is orbital theory of bonding in metals

lianna [129]

Metals of Group 1 donate 1 electron from its ns orbital to form ionic bond, where n is the no. of its outermost shell.
Metals of Group 2<span> donate 2 electrons from its ns orbital to form ionic bond, where n is the no. </span>of its <span>outermost shell. </span>

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3 years ago

In the lab, you looked at speed-time graphs to determine the acceleration of the cart for each of the three fan speeds

Bumek [7]

Answer:

What was the acceleration of the cart with Low fan speed? ⇒ 18.0 cm/s2

What was the acceleration of the cart with Medium fan speed? ⇒ 24.0 cm/s2

What was the acceleration of the cart with High fan speed? 32.0cm/s2

Explanation:

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3 years ago

Read 2 more answers

A sample of xenon occupies a volume of 736 mL at 2.02 atm and 1 °C. If the volume is changed to 416 mL and the temperature is ch

kozerog [31]

Answer:

$\large \boxed{\text{4.63 atm}}$

Explanation:

To solve this problem, we can use the Combined Gas Laws:

$\dfrac{p_{1}V_{1} }{n_{1}T_{1}} = \dfrac{p_{2}V_{2} }{n_{2}T_{2}}$

Data:

p₁ = 2.02 atm; V₁ = 736 mL; n₁ = n₁; T₁ = 1 °C

p₂ = ?; V₂ = 416 mL; n₂ = n₁; T₂ = 82 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = ( 1 + 273.15) K = 274.15 K

T₂ = (82 + 273.15) K = 355.15 K

(b) Calculate the new pressure

$\begin{array}{rcl}\dfrac{p_{1}V_{1}}{n_{1} T_{1}} & = & \dfrac{p_{2}V_{2}}{n_{2} T_{2}}\\\\\dfrac{\text{2.02 atm}\times \text{736 mL}}{n _{1}\times \text{274.15 K}} & = &\dfrac{p_{2}\times \text{416 mL}}{n _{1}\times \text{355.15 K}}\\\\\text{5.423 atm} & = &1.171{p_{2}}\\p_{2} & = & \dfrac{\text{5.423 atm}}{1.171}\\\\ & = & \textbf{4.63 atm} \\\end{array}\\\text{The new pressure will be $\large \boxed{\textbf{4.63 atm}}$}}$

6 0

2 years ago

Which element would be most likely to lose electrons in chemical bond

levacccp [35]

This the answer have a good day

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2 years ago