hopefully this helps. if it doesn't then I'm really sorry to say that I wouldn't know.
Answer:
0 587 mL
Explanation:
First we convert 180 grams of HCl into moles, using its molar mass:
- 180 g ÷ 36.46 g/mol = 4.94 mol HCl
Now we can <u>use the number of moles and the given concentration to calculate the required volume</u>, applying the <em>definition of molarity</em>:
- Molarity = moles / liters
- Liters = Moles / molarity
- 4.94 mol / 8.40 M = 0.588 L
Finally we <u>convert liters into milliliters</u>:
The closest answer is option C, 587 mL.
Answer:
Option A. 6.75 (6.20/85.6)
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 6.2cm³
Initial concentration (C1) = 6.75M
Final volume (V2) = 85.6cm³
Final concentration (C2) =.?
The final concentration can be obtained by using the dilution formula as show below:
C1V1 = C2V2
6.75 x 6.2 = C2 x 85.6
Divide both side by 85.6
C2 = (6.75 x 6.2) /85.6
C2 = 6.75 (6.2 / 85.6).
Early stages of carbon monoxide poisoning is often confused with seasickness or intoxication.
This is so because some symptons of carbon monoxide (CO gas) poisoning are: irritated eyes, headache, nause, weakness and dizziness. As you can see those symptons are common to seasickness and intoxitation.
Carbon monoxide (CO gas) is colorless and odorless, so it may be difficult to detect the exposure to it before having some symptons of CO poisoning, but it is serious and can result in death. The victim shall be conducted to an open place promptly to receive fresh air and carried to a hospital to receive treatment urgently.
Answer:
V=1.18 L
Explanation:
Alternative solution:
Calculate how many moles
2.34
g
C
O
2
is
2.34
g
⋅
1
m
o
l
44
g
C
O
2
=
0.053
m
o
l
Simple mole ratios tell us that
1
mol of any gas at STP is
22.4
L
, but since we only have
0.053
m
o
l
, we times
22.4
L
m
o
l
by
0.053
m
o
l
.
22.4
L
m
o
l
⋅
0.053
m
o
l
=
1.18
L
Answer link
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