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3 years ago

How many protons, electrons, and neutrons does 18F- contain?

Chemistry

2 answers:

Rom4ik [11]3 years ago

7 0

<h3>Answer:</h3>

Number of Protons = 9

Number of Neutrons = 9

Number of Electrons = 10

<h3>Explanation:</h3>

Number of Protons:

The number of protons present in any atom are equal to the atomic number of that particular atom. Hence, as the atomic number of Fluorine is 9 therefore, it contains 9 protons.

Number Neutrons:

The number of neutrons present in atom are calculated as,

# of Neutrons = Atomic Mass - # of protons

As given,

Atomic Mass = 18

# of Protons = 9

So,

# of Neutrons = 18 - 9

# of Neutrons = 9

Number of Electrons:

As we know for a neutral atom the number of electrons are exactly equal to the number of protons present in its nucleus. So, for 9 protons in neutral Fluorine atom there must be 9 electrons. But, we are given with Fluoride Ion (i.e. F⁻) so it contains one extra electron hence, it contains the total of 10 electrons respectively.

yaroslaw [1]3 years ago

6 0

Answer:

Number of Protons = 9

Number of Neutrons = 9

Number of Electrons = 10

Explanation:

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3 years ago

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4 years ago

The concentration of a biomolecule insdie a rod-shaped prokaryotic cell is 0.0051 M. Calculate the number of molecule inside the

Ann [662]

<u>Answer:</u> The number of molecules inside the cell are $2.2\times 10^6$

<u>Explanation:</u>

We are given a prokaryotic cell, which is in the shape of rod or cylinder.

The equation used to calculate the volume of cylinder is:

$V=\pi r^2h$

where,

V = volume of cell = ?

r = radius of the celle = $\frac{d}{2}=\frac{1.7\mu m}{2}=0.85\mu m=8.5\times 10^{-7}m$ (Conversion factor: $1m=10^6\mu m$ )

h = length of the cell = $3.1\mu m=3.1\times 10^{-6}m$

Putting values in above equation, we get:

$V=(3.14)\times (8.5\times 10^{-7})^2\times 3.1\times 10^{-6}\\\\V=7.033\times 10^{-18}m^3$

To calculate the number of moles for given molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of biomolecule = 0.0051 M

Volume of solution = $7.033\times 10^{-18}m^3=7.033\times 10^{-15}L$ (Conversion factor: $1m^3=1000L$ )

Putting values in above equation, we get:

$0.0051M=\frac{\text{Moles of biomoleculel}}{7.033\times 10^{-15}L}\\\\\text{Moles of biomolecule}=(0.0051mol/L\times 7.033\times 10^{-15}L)=3.59\times 10^{-17}mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, $3.59\times 10^{-17}$ moles of a biomolecule will contain = $(3.59\times 10^{-17}\times 6.022\times 10^{23}=2.2\times 10^6$ number of molecules

Hence, the number of molecules inside the cell are $2.2\times 10^6$

5 0

3 years ago