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Degger [83]
3 years ago
7

Explain the energy transformations necessary for turning on a Chromebook. Your description should have at least three types of e

nergy being described.
You may want to talk about the different parts of the Chromebook,such as:

Plug
Battery
Light

PLZ HELP THIS IS DUE TODAY!!
Physics
1 answer:
ad-work [718]3 years ago
6 0

Answer:

First, you need to charge the battery.

You do this by connecting the device to the electricity, in this way you can store the energy, that comes in form of electric energy, in the battery, that stores the energy in form of chemical energy.

When you push the "ON" button, the energy stored in the battery starts to run in the device, in form of electrical energy, in this way it reaches all the components and the computer is fully turned on.

At this moment the Chromebook turns on its screen, producing luminous energy (so consumes the electric energy that comes from the battery, and turns it into luminous energy).

There are other transformations, for example, in the cooler (the small fan inside the device) there is a transformation from electrical energy to mechanical energy (because the fan is rotating now).

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A 2kg mass is suspended on a rope that wraps around a frictionless pulley attached to the ceiling with a mass of 0.01kg and a ra
worty [1.4K]

Answer:

The torque on the pulley, when the system is motionless is approximately 9.81 N·m

Explanation:

The given parameters are;

The mass of the object = 2 kg

The friction between the rope and the pulley = 0

The mass of the rope, m_r = 0.5 kg

The mass of the pulley, m_p = 0.01 kg

The radius of the pulley, r = 0.25 m

The torque on the pulley, τ = I·α = F × D

The torque on the pulley, when the system is motionless, τ = F × D

Where;

F = The force acting on the pulley rope = The weight of the mass ≈ 2 kg × 9.81 m/s² = 19.62 N

D = The diameter of the pulley = 2×r = 2 × 0.25 m = 0.5 m

Therefore;

τ = 19.62 N × 0.5 m = 9.81 N·m

The torque on the pulley, when the system is motionless, τ ≈ 9.81 N·m.

4 0
3 years ago
A weight suspended from a spring is seen to bob up and down over a total distance of 20 centimeters twice each second.
Zielflug [23.3K]

<u>Answer</u>

8. 2 Hz

9. 0.5 seconds

10. 20 cm


<u>Explanation</u>

<u>Q 8</u>

Frequency is the number of oscillation in a unit time. It is the rate at which something repeats itself in a second.

In this case, the spring bob up and down 2 times per second.

∴ Frequency = 2 Hz

<u>Q 9</u>

Period is the time taken to complete one oscillation.

2 oscillations takes 1 second

1 oscillation = 1/2 seconds.

∴ Period = 0.5 seconds


<u>Q 10</u>

Amplitude is the the maximum displacement of the spring.

In this case the spring bob up 20 cm. This is it's displacement.

∴ Amplitude = 20 cm

5 0
3 years ago
What is transferred through sound waves?
alexandr402 [8]

Answer:

Sound waves transfer energy by causing successive compressions and rarefactions in the particles of the medium without transporting the medium particles themselves. Sound in solids can also manifest as transverse waves, causing crests and troughs in the propagation medium.

6 0
3 years ago
Given three different locations on Earth's surface, where will the weight of a person be greatest?
Feliz [49]

Answer:

Explanation:

In order to answer this question, we simply have to refer to the laws of the equations of gravitational mechanics.

The equation given by Newton tells us that  

F = \frac{Gm_{1} m_{2}  }{r^{2} }

In the case where we compare a specific place where the Force of Gravity is greater or lesser, we focus on the term assigned to the Planet's Radius.

In the case of G, m_{1} ,m_{2}, we understand that they are constant.

We can easily notice that the more the Radius (Height seen from a viewer on the ground), the lower the force will be.

In other words, the smaller the radius in which the measurement is made with respect to the center of the earth, the greater the gravitational force.

In that order of ideas the smallest radio has South Pole, which is about 6356 km from the center of the Earth on the Equator line

4 0
2 years ago
A 20 kg truck drives in a circle of radius 4 m at 10m/s. What is the centripetal acceleration of the truck?
asambeis [7]

Answer:

B. 25 m/s/s

Explanation:

Centripetal acceleration is the square of the tangential velocity divided by the radius of curvature.

a = v² / r

Given v = 10 m/s and r = 4 m:

a = (10 m/s)² / 4 m

a = 25 m/s²

4 0
3 years ago
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