Answer:
12.7m/s
Explanation:
Given parameters:
Mass of the diver = 77kg
Height = 8.18m
Unknown:
Speed of the diver before hitting the water = ?
Solution:
The speed of the diver before hitting the water is the final velocity.
To solve this problem, we use the expression below;
v² = u² + 2gH
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
H is the height
Now insert the parameters and solve;
v² = 0² + 2 x 9.8 x 8.18
v² = 160.328
v = 12.7m/s
Answer:
The height of the hill is, h = 38.42 m
Explanation:
Given,
The horizontal velocity of the soccer ball, Vx = 15 m/s
The range of the soccer ball, s = 42 m
The projectile projected from a height is given by the formula
S = Vx [Vy + √(Vy² + 2gh)] / g
Therefore,
h = S²g/2Vx² (Since Vy = 0)
Substituting the values
h = 42² x 9.8/ (2 x 15²)
= 38.42 m
Hence, the height of the hill is, h = 38.42 m
B is correct. Ever wondered why ice floats in water?
Answer:
h = 69.6 m
Explanation:
Data:
- Vo = 25 m/s
- t = 2.0 s
- g = 9.8 m/s²
- h = ?
Formula:
Replace and solve:
The building has a height of <u>69.6 meters.</u>
Greetings.
Answer:
volume is 0.1 L
Explanation:
you can use the equation density=mass/volume
100 = 1000 / v
divide by 1000 on both sides
0.1 = v
