Answer:
The valid quantum numbers are l=0, l=-2 and l= 2.
Explanation:
Given that,
n = 3 electron shell
Suppose, the valid quantum numbers are
l = 3
m = 3
l = 0
m = –2
l = –1
m = 2
We know that,
The value of n = 3
Principle quantum number :
Then the principal quantum number is 3. Which is shows the M shell.
So, n = 3
Azimuthal quantum number :
The azimuthal quantum number is l.
Magnetic quantum number :
The magnetic quantum number is
Hence, The valid quantum numbers are l=0, l=-2 and l= 2.
Answer:
-800 kJ/mol
Explanation:
To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).
First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:
Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol
moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄
Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:
ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol
Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).
The percent composition of this compound :
Mg = 72.182%
N = 27.818%
<h3>Further explanation</h3>
Given
9.03 g Mg
3.48 g N
Required
The percent composition
Solution
Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements
Total mass of the compound :
= 9.03 g + 3.48 g
= 12.51 g
The percent composition :
Mg : 9.03/ 12.51 g x 100% = 72.182%
N : 3.48 / 12.51 g x 100% = 27.818%
The answer would be uranium and thorium. When an alpha ejects a particle, it will create a new atom. So, when uranium ejects an alpha particle, it will produce thorium. They call this process as the alpha decay. Alpha decay often happens on atoms that are abundant nuclei such as uranium, radium, and thorium.
Water moves from an area of higher water potential (aka. "more water" in simple language) to an area of lower water potential (aka. "less water" in simple language).
For A, cells in carrots have water stored in their cytoplasm, where many soluble substances may be found (e.g. sodium ions). On the other hand, pure water has no other soluble substances other than the water molecules (I.e. H2O). Pure water will thus have a higher water potential as compared to the water in carrot cells, and so, water will move from pure water into the carrot cells via osmosis down a concentration gradient.
B. Corn syrup is water that has high concentrations of sugars, thus it is very likely to have a lower water potential than the cells of carrots. Water will move from within the cells of carrots and out to the corn syrup, down a concentration gradient.
C. The water in carrot cells will stay the same, since carrot cells have the same water potential as the surrounding solution which has the same water potential as cytoplasm.
Hope this helps! :)
