Answer:
Absolute pressure , P(abs)= 433.31 KPa
Explanation:
Given that
Gauge pressure P(gauge)= 50 psi
We know that barometer reads atmospheric pressure
Atmospheric pressure P(atm) = 29.1 inches of Hg
We know that
1 psi = 6.89 KPa
So 50 psi = 6.89 x 50 KPa
P(gauge)= 50 psi =344.72 KPa
We know that
1 inch = 0.0254 m
29.1 inches = 0.739 m
Atmospheric pressure P(atm) = 0.739 m of Hg
We know that density of Hg =
P = ρ g h
P(atm) = 13.6 x 1000 x 9.81 x 0.739 Pa
P(atm) = 13.6 x 9.81 x 0.739 KPa
P(atm) =98.54 KPa
Now
Absolute pressure = Gauge pressure + Atmospheric pressure
P(abs)=P(gauge) + P(atm)
P(abs)= 344.72 KPa + 98.54 KPa
P(abs)= 433.31 KPa
Answer:
a mass of water required is mw= 1273.26 gr = 1.27376 Kg
Explanation:
Assuming that the steam also gives out latent heat, the heat provided should be same for cooling the hot water than cooling the steam and condense it completely:
Q = mw * cw * ΔTw = ms * cs * ΔTw + ms * L
where m = mass , c= specific heat , ΔT=temperature change, L = latent heat of condensation
therefore
mw = ( ms * cs * ΔTw + ms * L )/ (cw * ΔTw )
replacing values
mw = [182g * 2.078 J/g°C*(118°C-100°C) + 118 g * 2260 J/g ] /[4.187 J/g°C * (90.7°C-39.4°C)] = 1273.26 gr = 1.27376 Kg
Answer:
you get electrocuted...........