Answer:
Explanation:
is the magnetic quantum number.
The only possible value for the magnetic quantum number for an electron in an s orbital is 0.
The first three quantun numbers are:
- n: principal quantum number. It may have positive integer values: 1, 2, 3, 4,5, 6, 7, ...
: Azimuthal or angular momentum quantum number. It may have integer values from 0 to n - 1.
This quantum number is related to the type (or shape) of the orbital:
For s orbitals
For p orbitals
For d orbitals
For f orbitals
In this case, it is an s orbital, so we have
.
, the third quantum number can have integer values
to 
Since, for the s orbitals
, the only possible value for
is zero.
Answer:
you have probably missed some details in the question.
Answer:
2.6×10⁻³ N
Explanation:
From coulomb's law,
F = kq'q/r²................ Equation 1
Where F = Repulsive force, q' = charge on the first sugar grain, q = charge on the second sugar grain, r = distance of separation between the sugar grain, k = proportionality constant.
From the question,
since q' = q
Then,
F = kq²/r²..................... Equation 2
Given: q = 1.79×10⁻¹¹ C, r = 3.45×10⁻⁵ m,
Constant: k = 9×10⁹ Nm²/kg².
Substitute into equation 2
F = 9×10⁹(1.79×10⁻¹¹)²/(3.45×10⁻⁵ )²
F = 9×10⁹(3.2041×10⁻²²)/(11.9025×10⁻¹⁰)
F = (28.8369×10⁻¹³)/(11.9025×10⁻¹⁰)
F = 2.6×10⁻³ N.