The steps in order to calculate the mass of a given volume of water is to use density. <span>Density is a physical
property of a substance that represents the mass of that substance per unit
volume. It is a property that can be used to describe a substance. Density slightly varies with changes in temperature so that it is important to determine the temperature.</span>
Answer:
Explanation:
the one thrown below the horizontal is going straight down, while the one above the horizontal will experience a projectile motion which will makes it move farther away from the building where it was projected.
<span>Interference can only be explained if light is a wave. Youngs Double Slit experiment proved this, proving the wave nature of light.</span>
m = Q(on moon) * G(on moon) = 200N * 1.63N/kg = 326kg
Q(Earth)= g * m = 10m/s2 * 326kg = 3260N
Answer:
Explanation:
Sam mass=75kg
Height is 50m
20° frictionless slope
Horizontal force on Sam is 200N
According to the work energy theorem, the net work done on Sam will be equal to his change in kinetic energy.
Therefore
Wg - Ww =∆K.E
Note initial the body was at rest at top of the slope.
Then, ∆K.E is K.E(final) - K.E(initial)
K.E Is given as ½mv²
Since initial velocity is zero then, K.E(initial ) is zero
Therefore, ∆K.E=½mVf²
Wg is work done by gravity and it is given by using P.E formulas
Wg=mgh
Wg=75×9.8×50
Wg=36750J
Ww is work done by wind and it's is given by using formulae for work
Work=force × distance
Ww=horizontal force × horizontal distance
Using Trig.
TanX=opposite/adjacent
Tan20=h/x
x=h/tan20
x=50/tan20
x=137.37m
Then,
Ww=F×x
Ww=200×137.37
We=27474J
Now applying the formula
Wg - Ww =∆K.E
36750 - 27474 =½×75×Vf²
9276=37.5Vf²
Vf²=9275/37.5
Vf²= 247.36
Vf=√247.36
Vf=15.73m/s
