Can you restate the question
we know that
Volume of a cone=(1/3)*[B]*h
where
B is he area of the base
h is the height
Find the volume of a cone in each case
case a) Raj
h=3 cm
diameter=5 cm
so
radius r=5/2=2.5 cm
Area of the base B=pi*r²
B=pi*2.5²
B=6.25*pi cm²
V=(1/3)*6.25*pi*3=6.25*pi cm³
case b) Amit
h=4 cm
r=3 cm
Area of the base B=pi*r²
B=pi*3²
B=9*pi cm²
V=(1/3)*9*pi*4=12*pi cm³
case c) Parul
h=7 cm
Area of the base B=4*pi cm²
V=(1/3)*4*pi*7=(9.33)*pi cm³
case d)Lara
h=6 cm
Area of the base B=3*pi cm²
V=(1/3)*3*pi*6=(6)*pi cm³
therefore
the answer is
Parul
I’m sorry I can only answer number 3. The coordinates should be 1,-5. I am really not sure tho, because I have never done anything like this
Answer:
x+16y
Step-by-step explanation:
4x-2(4x-6y) + 1/2(10x +8y)
4x-8x+12y+5x+4y
x+16y
are you sure about what you have written?
Answer:
(X+12)^2 -18-(24/2)^2
(X+12)^2 -18-144
(X+12)^2-162
Your answer is 1.
Step-by-step explanation:
