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kirill115 [55]
3 years ago
10

Use the periodic table to determine the number of valence electrons in each of the following elements.

Chemistry
2 answers:
pogonyaev3 years ago
5 0
Answer:
Na= 1, Ar= 8, V= 5, F= 7


Explanation:
You can determine the number of valence electrons in an element by looking the the group/column # on the periodic table. Elements in the same family/ group are organized by columns (vertical). Elements in the same column have the same number of valence electrons (electrons of the outermost shell) and consequently similar properties.
Simply put, GROUP #= # VALENCE E-

There are exceptions to this, especially when determining the amount of valence electrons in elements that are in a compound or in transition metal elements. For transition metals (that have different oxidation states- different # of valence electrons for the same element) I’d just look it up
Nina [5.8K]3 years ago
3 0

Answer:

Na:  1

F:    7

V:    5

Ar:   8

C:    4

Explanation:

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An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standar
Karolina [17]

Explanation:

First, we will calculate fuel consumption is as follows.

         372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s

           = 4526 g/s

Now, we will calculate the power as follows.

        Power = Fuel consumption rate × -enthalpy of combustion

                    = 4526 g/s \times -26.5 kJ/g

                    = 1.19 \times 10^{5} kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is 1.19 \times 10^{5} kW.

5 0
3 years ago
How are electric circuits like water in pipes list two ways
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8 0
3 years ago
A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.
GaryK [48]

Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂  +  I₂   ⇄   2HI

Initially we have 0.001 molesof H₂

and 0.002 moles of I₂

If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

           H₂     +      I₂      ⇄   2HI

In:     0.001       0.002           -

R:       x                 x                2x

Eq:  0.001-x    0.002-x      0.00187  

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵  moles of H₂

0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂

Expression for Kc is =  (HI)² / (H₂) . (I₂)

0.00187 ² /  6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

5 0
3 years ago
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