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kirill115 [55]
3 years ago
10

Use the periodic table to determine the number of valence electrons in each of the following elements.

Chemistry
2 answers:
pogonyaev3 years ago
5 0
Answer:
Na= 1, Ar= 8, V= 5, F= 7


Explanation:
You can determine the number of valence electrons in an element by looking the the group/column # on the periodic table. Elements in the same family/ group are organized by columns (vertical). Elements in the same column have the same number of valence electrons (electrons of the outermost shell) and consequently similar properties.
Simply put, GROUP #= # VALENCE E-

There are exceptions to this, especially when determining the amount of valence electrons in elements that are in a compound or in transition metal elements. For transition metals (that have different oxidation states- different # of valence electrons for the same element) I’d just look it up
Nina [5.8K]3 years ago
3 0

Answer:

Na:  1

F:    7

V:    5

Ar:   8

C:    4

Explanation:

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2 years ago
The percent yield of a reaction between elemental zinc and an aqueous solution of 0.50 M hydro-chloric acid is known to be 78.0%
Naddik [55]

Answer:

1.3 × 10³ mL

Explanation:

Let's consider the following reaction.

Zn + 2 HCl → ZnCl₂ + H₂

The percent yield is 78.0%. The real yield (R) of zinc chloride is 35.5 g. The theoretical yield (T) of zinc chloride is:

35.5 g (R) × (100 g T/ 78.0 g R) = 45.5 g T

The molar mass of zinc chloride is 136.29 g/mol. The moles corresponding to 45.5 g of zinc chloride is:

45.5 g × (1 mol/ 136.29 g) = 0.334 mol

The molar ratio of HCl to ZnCl₂ is 2:1. The moles of HCl that react with 0.334 moles of ZnCl₂ are 2 × 0.334 mol = 0.668 mol.

We need 0.668 moles of a 0.50 M HCl solution. The volume required is:

0.668 mol × (1000 mL/0.50 mol) = 1.3 × 10³ mL

3 0
3 years ago
How many grams of aluminum in required to produce 17.5 g of hydrogen
azamat

Mass of Aluminum = 157.5 g

<h3>Further explanation</h3>

Given

17.5 g of Hydrogen

Required

Mass of Aluminum

Solution

Reaction

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

mol Hydrogen :

= mass : molar mass

= 17.5 g : 2 g/mol

= 8.75

From the equation, mol Al :

= 2/3 x mol H₂

= 2/3 x 8.75

= 5.83

Mass Al :

= 5.83 x 27 g/mol

= 157.5 g

6 0
3 years ago
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