The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.
A(t) = A(o) (1/2)^(t/d)
where t is the certain period of time. Substituting the known values,
A(t) = (20 mg)(1/2)^(85.80/14.30)
Solving,
A(t) = 0.3125 mg
Hence, the answer is 0.3125 mg.
The balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃
- For any chemical equation to be balanced, the number of moles of elements in the reactants must be equal to that of the product.
- According to the question, we are to write a balanced equation for the reaction in aqueous solution for cesium carbonate and magnesium nitrate
- The chemical formula for Cesium carbonate is Cs₂CO₃
- The chemical formula for magnesium nitrate is Mg(NO₃)₂
Hence the balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃
Learn more here: brainly.com/question/11904811
<span>chemicals reacting are written on the left, what is formed is written on the right after the = sign
eg Copper + oxygen = copper oxide.
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Answer:
It can be removed by acidic chemicals
Explanation:
Answer: The molar mass and molecular weight of 4Fe is 223.38.
