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solmaris [256]
3 years ago
5

14. If you are asked to analyze an issue for an essay assignment, what should you do? a. Nb. C. Divide the issue into its main p

arts and discuss each part. Express your opinion about the issue. Explain what you think the issue means and how you came to that interpretation Describe the main ideas or points about the issue. d.​
Physics
1 answer:
ankoles [38]3 years ago
5 0

Answer:

Option C

Explanation:

Divide the issue into its main parts and discuss each part.

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What is dark energy? How is dark energy related to the theory of the multiverse?
olga55 [171]

Answer:

In the 1980s, astronomers turned to multiverse theory to explain the “luckily small” amount of dark energy in our universe. According to cosmologist's theories, this small amount of dark energy appeared to enable our universe to host life, while most universes in the multiverse couldn't.

Explanation:

4 0
4 years ago
A car is traveling north at 17.7 m/s . After 6 it’s velocity is 141 in the same direction. Find the magnitude and direction of t
Furkat [3]

By equation of motion we have   v = u + at

Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration

Here v = 141 m/s, u = 17.7 m/s and t = 6 s

On substitution we will get

        141 = 17.7+ 6a

       So, a = (141-17.7)/6 = 20. 55 m/s^{2}

       Aceeleration = 20. 55 m/s^{2} along north direction.


3 0
3 years ago
A 36,287 kg truck has a momentum of 907,175 kg • . What is the truck’s velocity?
Snowcat [4.5K]
By definition,
Momentum = Mass * Velocity

Let v =  the velocity of the truck, m/s
The mass of the truck is 36,287 kg.
The momentum is 907,175 (kg-m)/s.

Therefore
907,175 (kg-m)/s = (36287 kg)*(v m/s)
v = 907175/36287 = 25 m/s

Answer: 25 m/s

7 0
4 years ago
Read 2 more answers
A box is placed on a 30o frictionless incline. What is the acceleration of the box as it slides down the incline
balandron [24]

Answer:

<em>2.78m/s²</em>

Explanation:

Complete question:

<em>A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?</em>

According to Newton's second law of motion:

\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\

Where:

\mu is the coefficient of friction

g is the acceleration due to gravity

Fm is the moving force acting on the body

Ff is the frictional force

m is the mass of the box

a is the acceleration'

Given

\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2

Required

acceleration of the box

Substitute the given parameters into the resulting expression above:

Recall that:

gsin\theta - \mu g cos\theta = a_x\\

9.8sin30 - 0.25(9.8)cos30 = ax

9.8(0.5) - 0.25(9.8)(0.866) = ax

4.9 - 2.1217 = ax

ax = 2.78m/s²

<em>Hence the acceleration of the box as it slides down the incline is 2.78m/s²</em>

5 0
3 years ago
Calculate the normal force pushing up from the table in each example 8 kg
garik1379 [7]

The correct answer to the question is: 78.4 N.

EXPLANATION:

As per the question, the mass of the object is given as m = 8 Kg.

We are asked to calculate the normal force of the object.

The object is resting on the table.

Hence, the object pushes the table downward with a force equal to it's weight.

The table, in turn, pushes the object with the same force as given by the object, but in the upward direction.

The force given by the table on the object is known as the normal reaction of the object which acts perpendicular to the surface of the object.

Hence, the normal reaction is equal to the weight of the body.

The weight of a body is the product of it's mass with acceleration due to gravity.

So, the weight of 8 Kg object is calculated as -

Weight = mg

= 8 × 9.8 N.

= 78.4 N.

Here, g is known as acceleration due to gravity.

Hence, the normal force pushing up from the table is 78.4 N.







8 0
3 years ago
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