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NeTakaya
2 years ago
10

How many moles are in 15.0 grams of calcium (Ca)?

Chemistry
2 answers:
borishaifa [10]2 years ago
5 0
1 mol ---- 40g
X --------- 15g
X = 15/40 = 0,375 moles

:)
tatuchka [14]2 years ago
5 0

Answer:

The correct answer is option A.) 0.374 moles

Explanation:

Hello!

Let's solve this!

Calcium (Ca) has a mass of 40g / mol

In this case we have 15 g of Ca.

We need to calculate the amount of moles so the operation to be performed is as follows:

mol Ca = 15g * (1mol / 40g) = 0.375 mol

We conclude, after the calculations, that the correct answer is option A.) 0.374 moles

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Heating a substance causes molecules to speed up and spread slightly further apart, occupying a larger volume that results in a decrease in density. Cooling a substance causes molecules to slow down and get slightly closer together, occupying a smaller volume that results in an increase in density.

From: www.middleschoolchemistry.com

7 0
3 years ago
Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)
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Answer:

Rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

Explanation:

According to equation   2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

                     ⇒ -\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}  -----------------------------(1)

    Given that the rate of disappearance of oxygen = -\frac{d[O_{2} ]}{dt} = 3.64 x 10⁻³ M/s

             So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = ?

from equation (1) we can write

                                   \frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]

                                ⇒ \frac{d[SO_{3}] }{dt} = 2 x 3.64 x 10⁻³ M/s

                                ⇒ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

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3 years ago
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Learn more:

Ionization energy brainly.com/question/5880605

#learnwithBrainly

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<h3>Further explanation </h3>

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