6/3 Li is more stable due to it being composed of more than two stable isotopes.
<span>If a negatively charged rod is brought near a neutral metal sphere, no attraction would happen since the neutral sphere has no available positive charges. So, the rod won't be attracted to the sphere. Hope this answers the question. Have a nice day.</span>
Complete Similar Question
Use the method of cylindrical shells to find the volume V of the solid obtained by rotating the region bounded by the given curves about the x-axis.
On the first uploaded image is attached a graph of the shell
Answer:
The volume is V =
Explanation:
The explanation is shown on the second and third uploaded image
Answer:
(a) its moment of inertia about its center is 0.002095 kgm²
(b) Applied torque is 0.071813 Nm
Explanation:
Given;
Radius of the grinding wheel, R = 8.5cm
Mass of the grinding wheel, m = 0.580kg
Part (a) its moment of inertia about its center
I = ¹/₂MR²
I = ¹/₂(0.58)(0.085)²
I = 0.002095 kgm²
Part (b)
Given;
initial angular velocity, ωi = 1500rpm = 157.1 rad/s
final angular velocity, ωf = 1500rpm = 157.1 rad/s
Initial torque, τi = I x αi
αi = ωi / t
αi = 157.1 / 5 = 31.42 rad/s²
τi = 0.002095 x 31.42
τi = 0.06583 Nm
Final torque, τf = I x αf
αf = ωf / t
αf = 157.1 / 55 = 2.856 rad/s²
τf = 0.002095 x 2.856
τf = 0.005983 Nm
Applied torque = τi + τf
= 0.06583 Nm + 0.005983 Nm
= 0.071813 Nm