Correlational studies do not form the decision making or discussion because they do not offer conclusive evidence.
<h3>What are correlational findings?</h3>
The term correlational findings refers to research findings that only show the association between variables. This is a kind of research that does not establish causation but suggests a strong link between two variables.
This kind of study should not form the basis for decision making or discussion because they do not offer conclusive evidence about an issue. this kind of findings should e taken with a pinch of salt until the data is further confirmed by experimental studies.
Learn more about correlational findings:brainly.com/question/15411622
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Answer:
When the temperature of the gas is increased from 20 to 40, the pressure will be 2p
Explanation:
Given;
initial temperature of the gas, T₁ = 20 K
final temperature of the gas, T₂ = 40 k
initial pressure of the gas, P₁ = P
final pressure of the gas, P₂ = ?
Apply pressure law of gases;
Therefore, when the temperature of the gas is increased from 20 to 40, the pressure will be 2p
Answer:
374 N
Explanation:
N = normal force acting on the skier
m = mass of the skier = 82.5
From the force diagram, force equation perpendicular to the slope is given as
N = mg Cos18.7
μ = Coefficient of friction = 0.150
frictional force is given as
f = μN
f = μmg Cos18.7
F = force applied by the rope
Force equation parallel to the slope is given as
F - f - mg Sin18.7 = 0
F - μmg Cos18.7 - mg Sin18.7 = 0
F = μmg Cos18.7 + mg Sin18.7
F = (0.150 x 82.5 x 9.8) Cos18.7 + (82.5 x 9.8) Sin18.7
F = 374 N
Answer:
16.5% that of on earth
Explanation:
from google:
Your weight on the Moon is 16.5% what you would experience on Earth. In other words, if you weighed 100 kg on Earth, you would weigh a mere 16.5 kg on the Moon.
Answer:
0.182 m/s
Explanation:
m1 = 30,000 kg, m2 = 110,000 kg, u1 = 0.85 m/s
let the velocity of loaded freight car is v
Use the conservation of momentum
m1 x u1 + m2 x 0 = (m1 + m2) x v
30,000 x 0.85 = (30,000 + 110,000) x v
v = 0.182 m/s
