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Bezzdna [24]
3 years ago
6

Why is a block of gold is more dense than a block of iron of equal size?

Physics
1 answer:
baherus [9]3 years ago
6 0
Gold has almost 4 times the atomic weight of iron. Check the table of elements.D<span>ensity is Mass divided by its volume, right? Gold has a higher atomic weight than iron, so it will be much heavier.</span>
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A manufacturer supplies plastic cups that are placed under the legs of the chair
777dan777 [17]

A manufacturer supplies plastic cups that are placed under the legs of the chair. The manufacturer's claim is that there will be no marks of chair due to pushing or pulling on the floor.

<h3>Who is a manufacturer?</h3>

A manufacturer is a person who converts his idea of developing and constructing any item using some set of machines.

A manufacturer supplies plastic cups that are placed under the legs of the chair.

When there is a relative motion between two objects, friction force causes the opposition to this motion. Between chair and floor, there will be high magnitude of force. But if we insert plastic cups in the legs of chair, then the friction between cup and floor will be less. This keeps the floor protected form any scratches.

Learn more about manufacturer.

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2 years ago
What type of convergent boundary is the himalayan mountains formed by
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The Himalayan Mountains formed at a convergence plate boundary between the Eurasian plate and the Indian plate.

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3 years ago
I am pretty sure its the last one.
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The answer is has no moons. Mars has two moons
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7. Navy use SONAR method to locate the position of submarine under water. The waves used in SONAR are A transverse waves. B elec
pshichka [43]

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A. transverse waves

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An adiabatic nozzle has an inlet area of 1 m^2 and an outlet area of 0.25 m^2. Water enters the nozzle at a rate of 5 m^3/s and
svlad2 [7]

Answer:

v=20m/S

p=-37.5kPa

Explanation:

Hello! This exercise should be resolved in the next two steps

1. Using the continuity equation that indicates that the flow entering the nozzle must be the same as the output, remember that the flow equation consists in multiplying the area by the speed

Q=VA

for he exitt

Q=flow=5m^3/s

A=area=0.25m^2

V=Speed

solving for V

V=\frac{Q}{A} \\V=\frac{5}{0.25} =20m/s

velocity at the exit=20m/s

for entry

V=\frac{5}{1} =5m/s

2.

To find the pressure we use the Bernoulli equation that states that the flow energy is conserved.

\frac{P1}{\alpha } +\frac{v1^2}{2g} =\frac{P2} {\alpha } +\frac{v2^2}{2g}

where

P=presure

α=9.810KN/m^3 specific weight for water

V=speed

g=gravity

solving for P1

(\frac{p1}{\alpha } +\frac{V1^2-V2^2}{2g})\alpha  =p2\\(\frac{150}{9.81 } +\frac{5^2-20^2}{2(9.81)})9.81  =p2\\P2=-37.5kPa

the pressure at exit is -37.5kPa

7 0
4 years ago
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