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Alex
3 years ago
15

Need help with this problems

Chemistry
1 answer:
Fittoniya [83]3 years ago
3 0
16) Na (s) + H2O(L) ---> H2 (g) + NaOH (aq)
17) O2 (g) + NH3 (g) --->H2O (L) + HNO3 (aq)
18) K (s) + Cl2 (g) ---> KCl (s)
19) Al (s) + HCl (aq) ---> H2 (g) + AlCl (aq)
20) Na3PO4 (aq) + CaCl2 (aq) ---> NaCl (s) + Ca3(PO4)2 (s)
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Colt1911 [192]

Answer:

The volume is 2238,6 L

Explanation:

We use the formula PV=nRT. The conditions STP are: 1 atm of pressure and 273K of temperature:

PV=nRT ---> V=(nRT)/P

V= 100 mol x 0,082 l atm/K mol x 273K/ 1 atm

<em>V=2238, 6L</em>

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3 years ago
90 grams of glucose, C6H12O6, is dissolved in 2 liters of solution. Determine the molarity (M).
Masja [62]

Answer:

0.25 M

Explanation:

The first step is to determine how many moles of glucose there are, which means first finding out the molar mass of glucose. Carbon has a molar mass of about 12, hydrogen 1, and oxygen 16, so the total molar mass of glucose is about 6(12)+12(1)+6(16)=180 grams. This means that 90 grams is half a mole. Half a mole of substance divided by two liters of solution is (1/2)/2=1/4, or a molarity of 0.25. Hope this helps!

7 0
4 years ago
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