Definition: Asexual reproduction is a type of reproduction which does not involve the fusion of gametes or change in the number of chromosomes. The offspring that arise by asexual reproduction from a single cell or from a multicellular organism inherit the genes of that parent.
Types:
Budding- A form of asexual reproduction of yeast in which a new cell grows out of the body of a parent.
Vegetative Reproduction- Plants budding which creates a runner hich sends a clone
Strawberries plants
Dandelion
Parthenogenesis- An unfertilized egg develops into an adult (Aphids, honeybees, lizards)
Binary Fission- One cell splits into two cells
Allows for no genetic variety
Bacteria performs it
Protests perform it but takes longer
Regeneration- The ability to regrow a missing part of the body by Mitosis
Fragmentation- A small piece of an organism breaks away from it and develops into a new individual (star fish)
Spores- Contain DNA, cytoplasm, and tough putter wall protects it from dying out produced by many organisms (algae, fungi, bacteria)
Advantages: Allows rapid populating, does not need mates, does not require mobility, friendly to the environment, handy in case of emergency.
Disadvantage: poses some inheritance issues, can lead organism to being prude to extinction, carries problems with population control, causes organism to not be able to adapt and results in poor conditions to subject
IV: type of liquid used to water the plant (coca-cola, lemonade, water)
DV: height of growth
Control: time grown, same temperature and location
I can help you with part 1
Answer:
113 g NaCl
Explanation:
The Ideal Gas Law equation is:
PV = nRT
In this equation,
> P = pressure (atm)
> V = volume (L)
> n = number of moles
> R = 8.314 (constant)
> T = temperature (K)
The given values all have to due with the conditions fo F₂. You have been given values for all of the variables but moles F₂. Therefore, to find moles F₂, plug each of the values into the Ideal Gas Law equation and simplify.
(1.50 atm)(15.0 L) = n(8.314)(280. K)
2250 = n(2327.92)
0.967 moles F₂ = n
Using the Ideal Gas Law, we determined that the moles of F₂ is 0.967 moles. Now, to find the mass of NaCl that can react with F₂, you need to (1) convert moles F₂ to moles NaCl (via the mole-to-mole ratio using the reaction coefficients) and then (2) convert moles NaCl to grams NaCl (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).
1 F₂ + 2 NaCl ---> Cl₂ + 2NaF
Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol
Molar Mass (NaCl): 58.44 g/mol
0.967 moles F₂ 2 moles NaCl 58.44 g
---------------------- x ----------------------- x ----------------------- = 113 g NaCl
1 mole F₂ 1 mole NaCl
Answer:
89.1942....
Explanation:
abundance x mass on each one, the added all together:
77.742+6.201+5.251