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NeTakaya
3 years ago
8

If two geologic plates are sliding past each other, they are at a

Physics
2 answers:
kkurt [141]3 years ago
5 0

If two geologic plates are sliding past each other, they are at a transform boundary

makkiz [27]3 years ago
3 0
C. Transform boundary.
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Pilings are driven into the ground at a building site by dropping a 2250 kg object onto them. What change in gravitational poten
den301095 [7]

Answer: 324.135 kJ

Explanation:

Given

Mass of dropping is m=2250\ kg

The initial height of dropping is h_1=16\ m

The final height of dropping h_2=1.3\ m

Gravitational potential energy is the function of height i.e.

\Rightarrow \text{G.E.}=mgh

Change in Gravitational Energy is

\Rightarrow \Delta \text{G.E.}=mg(h_1-h_2)=2250\times 9.8\times (16-1.3)\\\\\Rightarrow \Delta \text{G.E.}=3,24,135\ J\approx 324.135\ kJ

5 0
2 years ago
Would you say the rate if cell growth is increasing or decreasing explain.​
gavmur [86]

Answer:

Cell growth is increasing.

The name is pretty self explanatory. But here is some facts.

  • <em>Cell growth is the multiplication of cells.</em>

<em><u> i hope this helped at all.</u></em>

5 0
3 years ago
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When the 5.0 kg cylinder fell 100 m, the final temperature of the water was
Luba_88 [7]

Answer: first blank- 26.17° C, second- 1.17 °C, third- 30.86°C, and last fourth- 5.86°C

Explanation:

Physics, got it right on edg. 2020:)

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3 years ago
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Potential energy can be converted into kinetic energy, a good example of this is when a pole-vaulter bends the pole during a lea
lesantik [10]

Answer:

The pole stores elastic potential energy when the pole is bent because its shape is change from its natural shape and it will want to go back to its original form, just like a spring or stretched elastic material.

Question:

Why did you lie about being in college?

6 0
3 years ago
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In a certain process, the energy change of the system is 250 \rm kJ. The process involves 480 \rm kJ of work done by the system.
alisha [4.7K]

Answer:

\Delta Q=-230kJ

Explanation:

Using the first law of thermodynamics:

\Delta U=\Delta Q-W

Where \Delta U is the change in the internal energy of the system, in this case  \Delta U=250kJ, \Delta Q is the heat tranferred, and W is the work,  W=-480kJ with a negative sign since the work is done by the system.

From the previous equation we solve for heat, because it is the unknown variable in this problem

\Delta Q=\Delta U +W

And replacing the known values:

\Delta Q=250kJ +(-480kJ)

\Delta Q=250kJ -480kJ

\Delta Q=-230kJ

The negative sign shows us that the heat is tranferred from the system into the surroundings.

3 0
3 years ago
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