You will use the formula PV=nRT
P = pressure
V = volume
n = moles
R = gas constant
T = Temperature
Since 21.4g of Ar (Argon) is given this will be divided by the molar mass of Ar to give you the number of moles. Mass of Ar is 40g so
21.4g/40g = 0.54 moles of Argon
Then you just change Celsius to Kelvin by adding 273 to 12.5 which will be
12.5 + 273 = 285.5 K
(The formula for changing C to K is
X°C + 273 = K)
Now with moles and temperature in K you can plug all your values into PV=nRT to find volume so
(1.25atm)V = (0.54moles)(0.0821)(285.5K)
(0.0821 is the gas constant R when using atm, Liters, moles, and kelvin; this should always be given by your teacher)
Multiply
1.25v= 12.66
Divide 1.25 on both sides
V= 12.66/1.25 —> 10.13L
Your answer should be approximately 10.13L
Answer: The bond length of the HI molecule is 158.0 pm
Explanation: Please see the attachment below
Answer:
a. 2,3-dimethylbutane < 2-methylpentane < n-hexane
Explanation:
The boiling point of alkanes is highly affected by the degree of branching in the molecule. Branched alkanes generally have a lower boiling point than unbranched alkanes.
The reason for the higher boiling point of unbranched alkanes is because they have greater vanderwaals forces acting between their molecules due to their larger surface area. Recall that branched alkanes have a lesser surface area compared to unbranched alkanes.
n-hexane is an unbranched alkane hence it will have the highest boiling point followed by 2-methyl pentane and lastly 2,3-dimethyl butane. The boiling point continues to decrease as the extent of branching increases.