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3 years ago

A golf ball and bowling ball are rolling at the same speed. Which has the greater momentum?

2 answers:

7 0

If a golf ball and a bowling ball are rolling at the same speed, use MSM as an analogy: More mass, more Speed, more Momentum. The golf ball is smaller, and may be going the same speed as the bowling ball but the bowling ball has a much greater mass than the golf ball. The bowling ball has the greater momentum. The bigger the object, the faster it goes, the more momentum it has.

raketka [301]3 years ago

5 0

The bowling ball has more momentum because it is bigger and has more weight to it than the golfball.

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1. The uniform seesaw is balanced at its center of mass. The smaller boy on the right has a mass of m = 40.0 kg. What is the mas

tankabanditka [31]

Answer:

Explanation:

Find the complete question attached

Using the principle of moment

Clockwise moment = Anticlockwise moment

AntiClockwise moment = M × 2.0

ACW moment = 2M

Clockwise moment = 40×4

Clockwise moment = 160kgcm

Equate both expression and calculate M

2M = 160

M = 160/2

M = 80kg

Hence the mass of his friend is 80kg

4 0

4 years ago

_____ is very corrosive and can cause rusting so metal tanks shouldn't be used

bagirrra123 [75]

Answer:

Iron

Explanation:

5 0

3 years ago

If a 60 kg student is standing on the edge of a cliff. Find the students gravitational potential of the cliff is 30 m high

kipiarov [429]

Answer:

17640J

Explanation:

Give mass m= 60kg

Height h =30m

Since the student is standing on the edge of a cliff , acceleration due to gravity g is 9.8m/s^2

The student’s gravitational potential energy can be found by the formula

mgh

That’s 60 x 9.8 x 30

= 17640J

8 0

3 years ago

A wire of length 26.0 cm carrying a current of 5.77 mA is to be formed into a circular coil and placed in a uniform magnetic fie

Olin [163]

Answer:

The maximum torque is $\tau_{max} = 1.139 *10^{-7} \ N \cdot m$

Explanation:

From the question we are told that

The length of the wire is $l = 26.0 \ cm = 0.26 \ m$

The current flowing through the wire is $I = 5.77mA = 5.77 *10^{-3} \ A$

The magnetic field is $B = 3.67 \ mT = 3.67 *10^{-3 } T$

The maximum torque is mathematically evaluated as

$\tau_{max} = \mu B$

Where $\mu$ is the magnetic dipole moment which is mathematically represented as

$\mu = \frac{I l^2}{4 \pi n }$

Where $n$ is the number of turns which from the question is 1

substituting values

$\mu = \frac{ 5.77 *10^{-3} * 0.26^2}{4 * 3.142* 1 }$

$\mu = 3.10 4* 10^{-5} A m^2$

Now

$\tau_{max} = 3.104 *10^{-5} * 3.67 *10^{-3}$

$\tau_{max} = 1.139 *10^{-7} \ N \cdot m$

7 0

3 years ago

Two 1.1 kg masses are 1 m apart (center to center) on a frictionless table. Each has +10 JC of charge. What is the initial accel

sweet-ann [11.9K]

Answer:

acceleration = 0.8181 m/s²

Explanation:

given data

mass = 1.1 kg

apart d = 1 m

charge q = 10 μC

to find out

What is the initial acceleration

solution

we know that acceleration is

acceleration = $\frac{force}{mass}$ .................1

here force = $k \frac{q1q2}{r^2}$

here q1 q2 is charge and r is distance and Coulomb constant k = 9 × $10^{9}$ Nm²/C²

force = $9*10^{9} \frac{(10*10^{-6})^2}{1^2}$

force = 0.9 N

so from equation 1

acceleration = $\frac{0.9}{1.1}$

acceleration = 0.8181 m/s²

6 0

3 years ago