The amplitude of a wave corresponds to its maximum oscillation of the wave itself.
In our problem, the equation of the wave is
![y(x,t)= (0.750cm)cos(\pi [(0.400cm-1)x+(250s-1)t])](https://tex.z-dn.net/?f=y%28x%2Ct%29%3D%20%280.750cm%29cos%28%5Cpi%20%5B%280.400cm-1%29x%2B%28250s-1%29t%5D%29)
We can see that the maximum value of y(x,t) is reached when the cosine is equal to 1. When this condition occurs,

and therefore this value corresponds to the amplitude of the wave.
The characteristics of the projectile launch allows to find the results for the questions about the movement of the ball are:
-
In the attached we see the vertical speed decreases with height and the curve is of the parabolic type.
- In the movement is several dimensions, each one is independent of the others, the movement in the x axis does not affect the movement in the y axis.
Kinematics studies the motion of bodies looking for relationships between position, velocity and acceleration. In the case of vertical and projectiles launch the acceleration on the vertical axis is the acceleration of gravity directed downward.
In the attachment we can see the position of the ball for two distances in the case of projectile launching.
We can see that the speed of the ball decreases with height according to the relation
y = go t - ½ g t²
Where y is the height, g is the initial vertical velocity, g is the acceleration of gravity and t is time.
In all movements in various dimensions we assume that each movement in an .
axis is independent
In the case of projectile launching, on the vertical axis there is an acceleration of gravity and on the horizontal axis there is no acceleration, the only parameter that this gives the two movements is the time, which is a scalar.
In conclusion, using the characteristics of the projectile launch, we can find the results for the questions about the movement of the ball are:
- In the movement is several dimensions, each one is independent of the others, the movement in the x axis does not affect the movement in the y axis.
- In the attached we see the vertical speed decreases with height and the curve is of the parabolic type.
Learn more about projectile launch here: brainly.com/question/24888457
Answer:
1. The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.
2. The person's image is 3.38 m tall.
Explanation:
From the given question, object distance, u = 0.75 m, object height = 1.8 m, radius of curvature of the reflecting globe, r = 8 cm = 0.08 m.
f =
=
= 0.04 m
1. The image distance, v, can be determined by applying mirror formula:
=
+ 
=
+ 
-
= 
= 
= - 
⇒ v = -
= - 1.41 m
The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.
2.
= 
= 
v = 
= 3.384
v = 3.38 m
The person's image is 3.38 m tall.
12.) Active transport because the cell must use energy to move large particles across the membrane.
13.) Photosynthesis takes place in plant leaves containing the chlorophyll pigment. Cellular respiration takes place in the cytoplasm and mitochondria of the cell. ... Cellular respiration uses glucose molecules and oxygen to produce ATP molecules and carbon dioxide as the by-product.
14.) In cells with a nucleus, as in eukaryotes, the cell cycle is also divided into two main stages: interphase and the mitotic (M) phase (including mitosis and cytokinesis). During interphase, the cell grows, accumulating nutrients needed for mitosis, and undergoes DNA replication preparing it for cell division.
Answer:
B: Energy that is transformed is neither created or destroyed
Explanation: