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Step2247 [10]
3 years ago
11

Wide shield-like mountains are formed from what type of lava?

Chemistry
2 answers:
Reptile [31]3 years ago
6 0
The answer is either D or B. hope this helps.
sasho [114]3 years ago
3 0

Answer:

C) is the correct answer! hope this helped ;)

Explanation:

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5.0 x 10^24 molecules equal
Ratling [72]
<span>4.999999999999999e</span>+<span>24 this is what i got on the calculator but i dont know if its right.</span>
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It takes 90 N of force to lift a box of books off my smiths table. If you can only leave the box 25% of the way up, how many new
leva [86]

Answer:3.6 I think sorry if wrong

Explanation:

90 divided by 25

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The process by which waste products are eliminated from the cell by diffusion through the cell membrane is called _____.
madam [21]

Answer:

Exocytosis

Explanation:

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2 years ago
Binary molecular (covalent) compounds are formed as the result of a reaction between two nonmetals. Although there are no ions i
ollegr [7]

Answer:

Binary molecular compounds are the compounds consisting of two non-metallic elements. Examples of binary molecular compounds include: NO2, HCl, HF, P2O5 e.t.c.

Rules For Naming Binary Molecular Compounds

Naming binary molecular compounds is quite easy,

1. The first element is given its name.

2. The second element is given its root name (such as, hydro, carb,ox, chlor e.t.c.) followed by suffix <em>ide.</em>

Name of N2O4 - Dinitrogen tetraoxide

Chemical Formula of;

 iodic acid: HI

disulfur trioxide: S2O3

dinitrogen monoxide: N2O

hydrofluoric acid: HF

Difference between Binary acid and an oxyacid

An oxyacid is an acid consisting of an oxygen atom bonded to a hydrogen atom and at least one other non-metallic element. Examples of oxyacids include HNO3, H2SO4 e.t.c.

Binary acids are the acids consisting of hydrogen atom bonded to a non-metallic element. Examples include HF, HCl, HI  e.t.c.

7 0
3 years ago
Read 2 more answers
Show all calculations. 1. 2 C 4 H 10 + 13 O 2 -&gt; 8 CO 2 + 10 H 2 O a) what mass of O 2 will react with 400 g C 4 H 10? b) how
bazaltina [42]

\\ \tt\hookrightarrow 2C_4H_10+13O_2\longrightarrow 8CO_2+10H_2O

  • 13mol of O_2 reacts with 2mols of C_4H_10.
  • 7.5mol of O_2 reacts with 1mol of C_4H_10

No of moles:-

\\ \tt\hookrightarrow \dfrac{Given\:mass}{Molar\:mass}

\\ \tt\hookrightarrow \dfrac{400}{58}

\\ \tt\hookrightarrow 6.89mol

Now

Moles of O_2

\\ \tt\hookrightarrow 7.5(6.89)=51.6mol

Mass of O_2

\\ \tt\hookrightarrow 51.6(32)=1651.2g

4 0
2 years ago
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