20 g O2 x 1 mol O2/32 g O = 0.625 mol O2
Answer:
You should follow these steps:
Count each type of atom in reactants and products.
Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances.
Repeat steps 1 and 2 until the equation is balanced.
Explanation:
<span>The elastic potential energy stored in the stretched rubber band changes to kinetic energy.</span>
Answer:
Density is 6.16g/L
Explanation:
<em>... at exactly -15°C and exactly 1atm...</em>
<em />
Using general gas law:
PV = nRT
We can find density (Ratio of mass and volume) in an ideal gas as follows:
P/RT = n/V
<em>To convert moles to grams we need to multiply the moles with Molar Weight, MW:</em>
n*MW = m
n = m/MW
P/RT = m/V*MW
P*MW/RT = m/V
<em>Where P is pressure: 1atm;</em>
<em>MW of chlorine pentafluoride: 130.445g/mol</em>
<em>R is gas constant: 0.082atmL/molK</em>
<em>And T is absolute temperature: -15°C+273.15 = 258.15K</em>
<em />
Replacing:
P*MW/RT = m/V
1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V
6.16g/L = m/V
<h3>Density of the gas is 6.16g/L</h3>
<em> </em>
