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denpristay [2]
4 years ago
12

Phosphate buffer solution is purchased as a(n) 10x stock solution. The solution is more concentrated than the working stock. If

tasked with making 75 mL of a 1x solution of PBS, how many mL of the stock solution would be needed
Chemistry
1 answer:
TiliK225 [7]4 years ago
6 0

Answer:

v₁ = 7.5mL

Explanation:

using the formula

m₁v₁=m₂v₂

given m₁=10x m₂=1x v₁=? v₂=75mL

10x × v₁ = 1x × 75mL

v₁ = 1x × 75mL / 10x

v₁ = 7.5mL

So, 7.5mL of 10x PBS should be added with 67.5mL of water

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Describe the process by which Ag+ ions are precipitated out of solution. 4. In your testing, several precipitates are formed, and then dissolved as complexes.
3 0
3 years ago
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How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?
Dominik [7]
The grams   of glucose  are  needed  to  prepare  400g  of  a 2.00%(m/m)  glucose  solution  g  is  calculated  as  below

=% m/m =mass  of the solute/mass  of  the  solution  x100

let mass of   solute  be represented  by  y
mass  of solution = 400 g
 % (m/m) = 2% = 2/100

 grams  of  glucose  is  therefore =2/100 =  y/400
by cross  multiplication

100y = 800
divide   both side  by  100

y= 8.0 grams



5 0
3 years ago
PLEASE HELP
nata0808 [166]

Answer:

Is this math? Cause as a fourth grader, I can do Algebra, but not this.

Explanation:

7 0
2 years ago
Which of the following is a radioactive element?Sodium, Fluorine,Oxygen <br> francium
Maksim231197 [3]

Answer:

Fluorine

Explanation:

These particles stick in the atoms and make them radioactive.

4 0
3 years ago
A 0.0000792 M sample of Compound X in a solvent has an absorbance of 0.341 at 528 nm in a 1.000-cm cuvet. The solvent alone has
natima [27]

Answer:

a) a = 3485 M⁻¹cm⁻¹

b) C = 0,000127 M

Explanation:

Lambert-Beer law says that there is a linear relationship between absorbance and concentration of a chemical substance. The formula is:

A = a×b×C

Where A is absorbance, a is molar absorptivity, b is path length and C is concentration.

a) In the problem Concentration is 0.0000792 M, b is 1,000cm and Absorbance is absorbance of sample-absorbance of blank: 0,341-0,065 = 0,276

Replacing:

0,276 = a×1,000cm×0,0000792M

<em>a = 3485 M⁻¹cm⁻¹</em>

b) As the experiment consist in the same compound in the same solvent, the molar absorptivity will be the same, a = 3485 M⁻¹cm⁻¹, path length will be 1,000cm and absorbance: 0,508-0,065 = 0,443

Replacing:

0,443 = 3485 M⁻¹cm⁻¹×1,000cm×C

<em>C = 0,000127 M </em>

<em></em>

I hope it helps!

8 0
3 years ago
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