Phosphate buffer solution is purchased as a(n) 10x stock solution. The solution is more concentrated than the working stock. If
1 answer:
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Answer:
The mass of water = 39.18 gm
Explanation:
Mass of iron = 32.5 gm
Initial temperature of iron = 22.4°c = 295.4 K
Specific heat of iron = 0.448
Mass of water =
Specific heat of water
Initial temperature of water = 336 K
Final temperature after equilibrium = 59.7°c = 332.7 K
When iron rod is submerged into water then
Heat lost by water = Heat gain by iron rod
(
-
) =
(
-
)
Put all the values in above formula we get
× 4.2 × ( 336 - 332.7 ) = 32.5 × 0.448 × ( 332.7 - 295.4 )
= 39.18 gm
Therefore the mass of water = 39.18 gm