All categories

4 years ago

Match the following vocabulary words with their definitions.

Physics

1 answer:

Licemer1 [7]4 years ago

3 0

Answer: (1) Putrefaction

(2) Biodegradable

(3) Refuse.

Putrefaction refers to decomposition of organic substances usually dead plants' and animals' bodies by microorganisms.

Therefore, it matches with first definition that states the decay of organic matter caused by microorganisms.

Biodegradable substances are decomposed by living organisms such as microorganisms.

Therefore, it matches with the second definition that states susceptible to decomposition by living organisms.

Refuse refers to something which is no longer useful.

Therefore, it matches with the third definition of waste.

You might be interested in

Select the correct answer.

chubhunter [2.5K]

I believe it’s self-referent encoding

3 0

3 years ago

Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A graduated cylinder contains

lakkis [162]

Given that the density of heptane is

$d_h=\frac{0.684g}{mL}$

The mass of heptane is

$m_h=31\text{ g}$

The density of water is

$d_w=\frac{1g}{mL}$

The mass of water is

$m_w=37\text{ g}$

The volume of heptane will be

$\begin{gathered} V_h=\frac{m_h}{d_h} \\ =\frac{31}{0.684} \\ =45.32\text{ mL} \end{gathered}$

The volume of water will be

$\begin{gathered} V_w=\frac{m_w}{d_w} \\ =\frac{37}{1} \\ =37\text{ mL} \end{gathered}$

Thus, the volume of heptane is 45.32 mL and the volume of water is 37 mL.

The total volume of liquid in the cylinder will be

$\begin{gathered} V=V_h+V_w \\ =45.32+37 \\ =82.32\text{ mL} \end{gathered}$

The total volume of liquid in the cylinder will be 82.32 mL.

7 0

1 year ago

Resisting force is

Alina [70]

Answer:

Explanation:

6 0

3 years ago

A student places a block on a table and hangs one mass from the block. The student lets the block go and observes the block move

NeTakaya

Magnitude of acceleration

Explanation:

We know that acceleration can increase depending in the force applied on an object, any object with a greater mass will apply a greater force. F = M(a).

7 0

3 years ago

1. A mass is on a level plane, it has a weight of 20N. What is the coefficient of kinetic friction if an applied force

Arturiano [62]

Answer:

0.4

Explanation:

F-Fr=ma where F is applied force, Fr is friction, m is mass and a is acceleration.

Since the mass is moving with a constant velocity, there's no acceleration hence

$F=Fr=\mu N$ where N is the weight of object and \mu is coefficient of kinetic friction.

$F=\mu N and making [tex]\mu$ the subject

$\mu=\frac {F}{N}$

Substituting F for 8 N and N for 20 N

$\mu=\frac {8}{20}=0.4$

Therefore, coefficient of kinetic friction is 0.4

4 0

4 years ago