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Nataly [62]
3 years ago
9

This force on compass dials is an example of a force that _______.

Physics
2 answers:
romanna [79]3 years ago
4 0
D. Acts at a distance, because magnetic forcefield is in two dots, Earth's north and south magnetic poles, and magnet is on some distance from them.
TEA [102]3 years ago
3 0

acts at a distance

is the answer

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An engineering firm is designing a ski lift. The wire rope needs to travel with a linear velocity of 2.0 meters per second, and
Mazyrski [523]

Answer:

The diameter of the bull-wheel is 3.82

Explanation:

Given that,

Velocity = 2.0 m/s

Angular velocity = 10 rev/m

\omega=10\times\dfrac{2\pi}{60}

\omega=1.0472\ rad/s

We need to calculate the diameter of bull-wheel

Using formula of angular velocity

v= r\omega

r=\dfrac{v}{\omega}

Put the value into the formula

r=\dfrac{2.0}{1.0472}

r=1.91\ m

The diameter of the bull-wheel

D=2r

D=2\times1.91

D=3.82\ m

Hence, The diameter of the bull-wheel is 3.82 m.

6 0
3 years ago
A guy wire 1034 feet long is attached to the top of a tower. When pulled taut, it touches level ground 699 feet from the base of
kolezko [41]

Answer:

80.386 degrees

Explanation:

We use the cosine equation here (which is the adjacent side of the unknown angle divided by the hypotenuse

The adjacent side = 699ft

The hypotenuse = 1034ft

using cos∅ = Adjacent/hypotenuse

where ∅ is the unknown angle

cos ∅ = 699/1034 = 0.167

∅ = arccos 0.167 = 80.368°

As easy as one can imagine

8 0
2 years ago
Suppose you have a 113-kg wooden crate resting on a wood floor. (μk = 0.3 and μs = 0.5) (a) What maximum force (in N) can you ex
AURORKA [14]

Answer:

554.27N

Explanation:

(a)  The max frictional force exerted horizontally on the crate and the floor is,

Substitute the values,

μs=0.5

mass=113kg

g=9.81m/s

Ff=μsN

   =μsmg

   =(0.5 x 113 x 9.81)

Ff=554.27N

3 0
3 years ago
A 4 V power source is connected in parallel to four resistors: 1, 2, 2, and 3. Find the total current.
Keith_Richards [23]

Answer:

Explanation:

Equivalent resistance is 1 / ((1/1) + (1/2) + (1/2) + (1/3)) = 3/7 Ω

I = V/R = 4(7/3) = 28/3 = 9.3 A    

4 0
2 years ago
How much force is required to accelerate a 22Kg mass at 6 m/s?
GuDViN [60]

Answer:

F = 132N

Explanation:

7 0
3 years ago
Read 2 more answers
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