Answer:
The force of gravitational attraction is 8.454 x 10⁻⁸ N.
Explanation:
Given;
mass of the boy, m₁ = 78 kg
mass of the girl, m₂ = 65 kg
distance between the boy and the girl, r = 2 meters
The force of gravitational attraction is given as;
where;
G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²
r is the distance between two masses, m₁ and m₂
Therefore, the force of gravitational attraction is 8.454 x 10⁻⁸ N.
0.118 m is the distance between the two protons.
Mass of proton = 1.6726 × 10⁻²⁷ kg
Weight of proton= 1.6726 × 10⁻²⁷ x 9.81 N
= 1.6408 × 10⁻²⁶ N
Charge of proton = 1.602 × 10⁻²⁹ C
The force between two protons = kq²/r² where, K is a proportionality
constant, q is a charge of proton and
r is the distance between two protons.
= 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
To calculate distance :
Weight of proton= Force between protons
⇒ 1.6408 × 10⁻²⁶ N = 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
⇒ r = 0.118m
Therefore, 0.118 m is the distance between the two protons.
Learn more about electrostatic force here:
brainly.com/question/18108470
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Answer:
a = 1.34 m/s²
Explanation:
given,
mass of the attendant(M) = 75 Kg
mass of cart (m)= 27 Kg
Backward force exerted on floor (F)= 155 N
frictional force on the cart (f)= 18 N
acceleration
F_{net} = F - frictional force
F_{net} = 155 N - 18 N
F_{net} = 137 N
now,
a = 1.34 m/s²
the acceleration produced when flight attendant is equal to a = 1.34 m/s²
F = ma
Rearrange this so acceleration is the subject:
A = f/m
Now input your values into this equation for the first question :
A = f/m
A = 15/45
A = 0.33333333 m/s
Then using this same equation change the force of 15 to 25 :
A = f/m
A = 25/45
A = 0.55555556 m/s
For the last question keep the force of 15N but change the mass to 70kg into the same equation :
A = f/m
A = 15/70
A = 0.21 m/s (rounded)