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garri49 [273]
3 years ago
10

a truck of mass 2 500 kg travelling at the speed of 20 ms–1 to the right collide head-on with another car of mass 1 000 kg. If b

oth the truck and the car stop after collision, what is the velocity of the car before the collision?​
Physics
1 answer:
monitta3 years ago
4 0

Answer:

50 m/s opposite direction to the motion of the truck

Explanation:

From the question,

Applying the law of conservation of momentum

mu+m'u' = V(m+m')...….. Equation 1

Where m = mass of the truck, u = initial velocity of the truck, m' = mass of the car, u' = initial velocity of the car, V = Final velocity after collision

Given: m = 2500 kg, u = 20 m/s, m' = 1000 kg, V = 0 m/s (both car stop after collision)

Substitute these values into equation 1

2500(20)+1000(u') = 0(2500+1000)

2500(20)+1000(u') = 0

Solve for u'

u' = -[2500(20)]/1000

u' = -50 m/s

The negative sign shows that the car travels in opposite direction to the truck

Hence the car initial velocity before collision is 50 m/s in opposite direction to the motion of the truck

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qaws [65]

-- We know that the y-component of acceleration is the derivative of the
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-- We know that the y-component of velocity is the derivative of the
y-component of position.

-- We're given the y-component of position as a function of time.

So, finding the velocity and acceleration is simply a matter of differentiating
the position function ... twice.

Now, the position function may look big and ugly in the picture.  But with the
exception of  't' , everything else in the formula is constants, so we don't even
need any fancy processes of differentiation.  The toughest part of this is going
to be trying to write it out, given the text-formatting capabilities of the wonderful
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From the picture . . . . . y (t) = (1/2) (a₀ - g) t² - (a₀ / 30t₀⁴ ) t⁶

First derivative . . . y' (t) = (a₀ - g) t  -  6 (a₀ / 30t₀⁴ ) t⁵  =  (a₀ - g) t  -  (a₀ / 5t₀⁴ ) t⁵

There's your velocity . . . /\ .

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and there's your acceleration . . . /\ .
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Pick, or look up, some reasonable figures for a₀ and t₀
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The big name in model rocketry is Estes.  Their website will give you
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6 0
3 years ago
A 1.0-kg block and a 2.0-kg block are pressed together on a horizontal frictionless surface with a compressed very light spring
Lunna [17]

Answer:

statement B is true

Explanation:

since same force is applied by the compressed spring on both masses so their rate of change of momenta must be same and since the lighter block has lesser mass so it must have greater velocity to have an equal change in momentum as of heavier mass.

By relation: KE=\frac{(mv)^{2} }{2m}

KE lighter=\frac{(mv)^{2} }{2(1)} , KEheavier=\frac{(mv)^{2} }{2(2)}

comparing momenta of above two equations we get

KElighter (2) = KEheavier (4)

KElighter = 2 KEheavier

7 0
4 years ago
All objects in the universe radiate some form of energy.<br> a. True<br> b. False
Harrizon [31]

That's true.  The only way to stop an object from radiating energy
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Of course it also absorbs heat at the same time, mostly from the
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3 0
4 years ago
Read 2 more answers
4.
Roman55 [17]

Inertia is directly related to Mass .

<u>Explanation</u>:  

Mass means that the amount of matter of an object. Inertia indicates the resistance of the physical object. The object with high mass have more inertia too. The mass and inertia both are directly proportional to each other. Mass is the quantity that completely depends upon the inertia of the object. An object with more mass has more chance to change its resistance as they are dependent on each other.

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Makovka662 [10]

Answer:

Explanation:

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Note that the term "period" is the time taken by a transverse wave to complete one oscillation. So if we know the number of oscillation made in one second by the wave and the total oscillation made, then we can know determine how long it will take a transverse wave to propagate from one end of the string to the other

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