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nataly862011 [7]

3 years ago

7

This is when atoms of elements combine by sharing electrons or by the complete transfer of electrons from one atom to another.

2 answers:

Marat540 [252]3 years ago

7 0

Well theres not a question but a covalent bond is when you share electrons.

creativ13 [48]3 years ago

4 0

Answer:

Covalent bond

Explanation:

When two atoms have shared electrons, it is not distinguishable from what atom they are because they are shared in the same orbit, it is called a covalent bond.

Atoms in a covalent bond share one or more electrons in the last of their orbitals, the number of electrons in the last orbital will depend on the element in question.

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How is a joule defined?

andreyandreev [35.5K]

Answer:

A. It is the work done when a force of 1 newton is applied to an object for a distance of 1 meter

Explanation:

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3 years ago

4NH3 + 5O2-> 4NO + 6H2O<br><br> How many molesof NO are formed if 824g of NH3 react ?

ZanzabumX [31]

824 g NH3 (1 mol/17 g NH3) (4 mol NO/4mol NH3)

48.47 moles NO

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3 years ago

Calculate the standard reaction Gibbs free energy for the following cell reactions: (a) 2 Ce41(aq) 1 3 I2(aq) S 2 Ce31(aq) 1 I32

Law Incorporation [45]

<u>Answer:</u>

<u>For a:</u> The standard Gibbs free energy of the reaction is -347.4 kJ

<u>For b:</u> The standard Gibbs free energy of the reaction is 746.91 kJ

<u>Explanation:</u>

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$ ............(1)

<u>For a:</u>

The given chemical equation follows:

$2Ce^{4+}(aq.)+3I^{-}(aq.)\rightarrow 2Ce^{3+}(aq.)+I_3^-(aq.)$

<u>Oxidation half reaction:</u> $Ce^{4+}(aq.)\rightarrow Ce^{3+}(aq.)+e^-$ ( × 2)

<u>Reduction half reaction:</u> $3I^_(aq.)+2e^-\rightarrow I_3^-(aq.)$

We are given:

$n=2\\E^o_{cell}=+1.08V\\F=96500$

Putting values in equation 1, we get:

$\Delta G^o=-2\times 96500\times (+1.80)=-347,400J=-347.4kJ$

Hence, the standard Gibbs free energy of the reaction is -347.4 kJ

<u>For b:</u>

The given chemical equation follows:

$6Fe^{3+}(aq.)+2Cr^{3+}+7H_2O(l)(aq.)\rightarrow 6Fe^{2+}(aq.)+Cr_2O_7^{2-}(aq.)+14H^+(aq.)$

<u>Oxidation half reaction:</u> $Fe^{3+}(aq.)\rightarrow Fe^{2+}(aq.)+e^-$ ( × 6)

<u>Reduction half reaction:</u> $2Cr^{2+}(aq.)+7H_2O(l)+6e^-\rightarrow Cr_2O_7^{2-}(aq.)+14H^+(aq.)$

We are given:

$n=6\\E^o_{cell}=-1.29V\\F=96500$

Putting values in equation 1, we get:

$\Delta G^o=-6\times 96500\times (-1.29)=746,910J=746.91kJ$

Hence, the standard Gibbs free energy of the reaction is 746.91 kJ

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3 years ago

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Leya [2.2K]

generally bacteria reproduce by binary fission

3 0

3 years ago

Read 2 more answers

The atomic number of magnesium is 12 this is also the number of which of the following

frozen [14]

The atomic number represents the number of protons present in an atom.Therefore,the answer is B.

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3 years ago