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3 years ago

What is the magnitude of δv12 if the bulb is removed from the socket (i.e. the circuit is not closed)?

Physics

2 answers:

zloy xaker [14]3 years ago

7 0

If the socket is open after removing the bulb, then the substitute value is
I = 0 A
ΔV₁₂ = IR
= (OA)(2Ω)
= 0 V

andreev551 [17]3 years ago

4 0

Since the circuit is incomplete or not closed, no current flows in the circuit. as per ohm's law , Voltage is directly proportional to current and is given as

V = Voltage = i R where i = current , R = resistance

as no current flows in the circuit, i = 0

the resistance R can not be zero. hence

V = 0 (R)

V = 0 Volts

so the magnitude of the Voltage is zero Volts

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