Answer:
![K=\frac{[CaO][CH_{4}][H_{2}O ]^{2} }{[CaCO_{2}][H_{2}]^4 }](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCaO%5D%5BCH_%7B4%7D%5D%5BH_%7B2%7DO%20%5D%5E%7B2%7D%20%20%7D%7B%5BCaCO_%7B2%7D%5D%5BH_%7B2%7D%5D%5E4%20%20%7D)
Explanation:
The equilibrium expression is the K value equal to the product of the concentrations of the products over the product of the concentrations of the reactants. If there is a coefficient in front of the compound, raise the molecule to that power.
Since K is big, more product is expected. This is because of mathematic principles. A large numerator with a small denominator will produce a large number.
1-PRIMARY ALKANOL 2-SECONDARY ALKANOL 3-TERTIARY ALKANOL
Answer:
A reaction in which one element replaces another element in a compound.
Answer:
- <u><em>No, I would not consider a metal to be a plasma because plasma is just another state of matter, and the copper wire is in solid state.</em></u>
Explanation:
Metal is not a state of matter. Metals can be solid or liquid (molten) depending on their melting point and the temperature at which they are.
Plasma is a state of matter, similar to gas, but it is reached only at very high temperatures like in the Sun. The particles in plasma state are not neutral atoms or molecules but negatively charged ions and electrons.
The copper wire is yet a solid, thus it cannot be considered a plasma.
Metals can be in plasma state only if the temperature is too high, like the temperatures in the stars. In fact, the metals in the Sun and other hotter stars are in plasma state.
Answer:Gained, Lost , Shared
Explanation:
The oxidation state tells you how many electrons an atom has GAINED.................. , LOST....................... , or SHARED........................ , in forming a compound.
Oxidation state is defined as the the total number of electrons that an atom gains or loses when forming a chemical bond with another atom.
----To form an ionic bond for example in NaCl, Na, with 11 electrons and one valence electron in its outermost shell donates or lose that valence electron to Chlorine with 17 electron and 7 in its outermost shell. Therefore Sodium, Na acquires the +1 oxidaton state to become stable and Chlorine acquires the -1 oxidation state to become stable forming the NaCl compound.
To form a covalent compound, There must be sharing of electrons between atoms.For example, in PCl3, The phosphorous atom with atomic number 15 shares its three unpaired electrons with the single valence electrons of three chlorine atoms. making the four molecules to attain stability with Phosphorous having +3 and the chlorine atoms having -1 oxidation states
