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3 years ago

How can an atom that has seven valence electrons complete its outermost level

2 answers:

3 0

It can form a covalent bond with a hydrogen bond that has one valence electron to have eight valence electrons and become stable.

Oksana_A [137]3 years ago

3 0

Answer: The element needs to react with other element by gaining an electron to complete its valence electron.

Explanation: The element which exhibit 7 valence electrons are halogens. They readily react with other element, for example: Hydrogen and Sodium, in order to gain an electron to complete their outermost shell.

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A solution is a homogenous mixture of solute and solvent. there are different types of solutions. a carbonated drink is an examp

bezimeni [28]

The following statements are correct:
ZINC SULPHATE ARE SOLUBLE IN WATER.
TABLE SALT DISSOLVES IN WATER TO FORM A SOLUTION.
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4 years ago

Read 2 more answers

How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2

jeyben [28]

<u>Answer:</u> The amount of barium sulfate produced in the given reaction is 0.667 grams.

<u>Explanation:</u>

To calculate the number of moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol$

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)$

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = $\frac{1}{1}\times 0.00286mol=0.00286mol$ of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

$0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g$

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

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3 years ago

What exactly is arsenic and what is it usted for

zaharov [31]

Answer:

it's a poison used to kill people in old times sry if it's wrong

Explanation:

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3 years ago

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LekaFEV [45]

The answer would be a Group.

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katrin [286]

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3 years ago