Im pretty sure th answer is D: temp differences on earth surface
The reaction between the lead iodide, PbI2 and sodium carbonate, Na2CO3, will form the chemical compounds, sodium iodide and lead carbonate as shown below.
PbI2 + Na2CO3 --> NaI + PbCO3
The white precipitate formed in the reaction is PbCO3.
Answer:
solid and liquid state respectively
Answer:
Solution A: 3.21% (m/v) NaCl ⇒ CRENATION
Solution B: 1.65% (m/v) glucose ⇒ HEMOLYSIS
Solution C: distilled H₂O ⇒ HEMOLYSIS
Solution D: 6.97% (m/v) glucose ⇒ CRENATION
Solution E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl ⇒ CRENATION
Explanation:
Isotonic solution = 0.9% (m/v) NaCl or 5.0% (m/v) glucose
<u>Crenation</u> will occur if the solution has a concentration higher than 0.9% (m/v) NaCl or 5.0% (m/v) glucose (hypertonic solution). This will occur in the following solutions:
Solution A: 3.21% (m/v) NaCl > 0.9% (m/v) NaCl
Solution D: 6.97% (m/v) glucose > 5.0% (m/v) glucose
Solution E: 5.0% (m/v) glucose <u>and</u> 0.9%(m/v) NaCl (the addition of the 2 components exceeds the osmotic pressure permitted).
<u>Hemolysis</u> will occur if the solution has a concentration lower than 0.9% (m/v) NaCl or 5.0% (m/v) glucose (hypotonic solution). This is the case of:
Solution B: 1.65% (m/v) glucose < 5.0% (m/v) glucose
Solution C: distilled H₂O = 0% glucose/0% NaCl < 0.9% (m/v) NaCl or 5.0% (m/v) glucose
