Answer:
A). 2.3 s
Explanation:
Given that,
Length of the string = 130cm or 1.3 m
g near Earth's surface = 9.8 
To determine the period of a pendulum near Earth’s surface;
T = 2 π 
T = 2π
T = 2.3 sec
Therefore, the period of the pendulum near the earth's surface is 2.3 sec.
Explanation:
Hey, there!
The liquid pressure varies with depth because liquid pressure is directly proportional to the depth of liquid from the free surface of the liquid. so, more the depth more the pressure and less the depth less the pressure.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
25.10 or 24.6m/s both answers are correct
Explanation:
firstly , divide the multiply with 2 and divide the result by acceleration due to gravity which is 9.8m/s or 10m/s
123*2=246
246/9.8 or 10
= 25.10 or 24.6m/s
