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saveliy_v [14]
3 years ago
10

PLEASE HELP ASAP 36. The Doppler Effect applies to light in addition to sound. What do you call the phenomenon that causes dista

nt stars and galaxies to appear as if they are moving away from the Earth (indicating the Universe is expanding)?
Physics
1 answer:
skad [1K]3 years ago
3 0

Answer:

It's probably the Redshift and Blueshift

Explanation:

The light shifting towards shorter or longer wavelengths as objects in space (stars or galaxies) move closer or farther away from us. This phenomenon is known as the Redshifts and Blueshifts. The concept indicates us that the Universe is expanding.

Hope this helps you!

Bye!

You might be interested in
As a 3.0 kg bucket is being lowered into a 10 m deepwell, starting from top, the tension in the rope is 9.8 N. theacceleration o
777dan777 [17]

Answer:

A) 6.5 m/s²

Explanation:

Mass of the bucket, m = 3.0 kg

depth of the well, d = 10 m

tension on the rope, T = 9.8 N

The net downward force on the bucket is given as;

T = mg - ma

where;

a is downward acceleration of the bucket

9.8 = (3 x 9.8) - 3a

9.8 = 29.4 - 3a

3a = 29.4 - 9.8

3a = 19.6

a = 19.6 / 3

a = 6.53 m/s² downwards

Therefore, the acceleration of the bucket is 6.53 m/s² downwards

8 0
3 years ago
What is the wavelength of light that is deviated in the first order through an angle of 13.1 ∘ by a transmission grating having
faltersainse [42]

Answer:

The wavelength of light is 4.53\times10^{-7}\ m

Explanation:

Given that,

Angle = 13.1°

Number of slits = 5000

We need to calculate the wavelength of light

Diffraction of first order is defined as,

d \sin\theta=n\lambda.....(I)

The separation of the slits

d = \dfrac{1}{N}

d=\dfrac{1}{5000}

d=2\times10^{-6}\ m

Now put the value in equation (I)

2\times10^{-6}\sin13.1^{\circ}=\lambda

Here, n = 1

\lambda=4.53\times10^{-7}\ m

Hence, The wavelength of light is 4.53\times10^{-7}\ m

7 0
3 years ago
D. What is the net force on the bowling ball rolling lane
3241004551 [841]

Answer:

Friction

Explanation:

3 0
2 years ago
Death Star has a diameter of 160,000m and a mass of 5.1e17kg. Millennium Falcon has a mass of 1.36e6kg (data from Wookieepedia)
lions [1.4K]

Answer:

7229 N

Explanation:

The gravitational force between the Death Star and the Millenium Falcon is given by:

F=G\frac{mM}{R^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

M=5.1\cdot 10^{17} kg is the mass of the Death Star

m=1.36\cdot 10^6 kg is the mass of the Millennium Falcon

R=\frac{160,000 m}{2}=80,000 m is the radius of the Death Star

Substituting numbers into the equation, we find the force

F=(6.67\cdot 10^{-11})\frac{(1.36\cdot 10^6 kg)(5.1\cdot 10^{17} kg)}{(80,000 m)^2}=7229 N

5 0
3 years ago
Calculate the magnitude of the total impulse applied to the car to bring it to rest
n200080 [17]

Answer:

Total impulse = mv = Initial momentum of the car

Explanation:

Let the mass of the car be 'm' kg moving with a velocity 'v' m/s.

The final velocity of the car is 0 m/s as it is brought to rest.

Impulse is equal to the product of constant force applied to an object for a very small interval. Impulse is also calculated as the total change in the linear momentum of an object during the given time interval.

The magnitude of impulse is the absolute value of the change in momentum.

|J|=|p_f-p_i|

Momentum of an object is equal to the product of its mass and velocity.

So, the initial momentum of the car is given as:

p_i=mv

The final momentum of the car is given as:

p_f=m(0)=0

Therefore, the impulse is given as:

|J|=|p_f-p_i|=|0-mv|=|-mv|=mv

Hence, the magnitude of the impulse applied to the car to bring it to rest is equal to the initial momentum of the car.

5 0
3 years ago
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