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Lyrx [107]
2 years ago
12

A solution 0.20 molar in monomer (styrene) and 4.0 X 10-3 M in benzoyl peroxide initiator is heated at 60°C. kp = 145 liter/mole

-sec, kt = 7.0 X 107 liter/mole-sec, f = 1, and the initiator half-life is 44 hr.
a) Draw the structure of the final polymer. (5 pts)


b) Draw the reaction mechanism for the polymerization including chemical structures formed in each of the three critical steps. (15 pts)


c) How long will it take to achieve 50% conversion? (20 pts)

Chemistry
2 answers:
fomenos2 years ago
8 0

Answer:

See explaination and attachment

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

A polymer is a chemical compound with molecules bonded together in long, repeating chains.

polymerization is a process of reacting monomer molecules together in a chemical reaction to form polymer chains or three-dimensional networks.

Please see attached files.

Elden [556K]2 years ago
4 0

Answer:

Part A and B are attached

Explanation:

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The reduction of nitrogen monoxide is described by the following chemical equation: 2H2 (g) +2NO (g) 2H20 ()N2 (g Suppose a two-
Ipatiy [6.2K]

Answer:

Reasonable Second step- N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

Explanation:

The given single step chemical reaction is as follows.

2H_{2}(g)+2NO \rightarrow 2H_{2}O(g)+N_{2}(g)

Suppose a two-step mechanism is proposed for this reaction,

The reaction occured in two steps they are as follows.

Step -1:H_{2}(g)+2NO \rightarrow N_{2}O(g)+H_{2}O(g)

Step-2:N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

8 0
3 years ago
A student conducts an experiment to determine the effect of adding salt on the boiling temperature of water. The results are sho
sineoko [7]

Answer:

The answer to your question is: The first option is correct.

Explanation:

From the data given, we conclude that as the amount of salt increases, the boiling point of water increases.

Options

If salt is added to water, the water will boil at a higher temperature This is the hypothesis for the experiment.

Salt makes water boil. This statement is not true.

If water is boiling, it must have salt added to it. This statement is incorrect, it is not the goal of the experiment.

If salt is added to water, the water will get cloudy There is not evidence of that from the information given.

3 0
3 years ago
Read 2 more answers
A 20.0-milliliter sample of 0.200 M K2CO3 solution is added to 30.0 milliliters of 0.400 M Ba(NO3)2 solution.
jenyasd209 [6]

Answer:

(B) 0.160 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For K_2CO_3 :

Molarity = 0.200 M

Volume = 20.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 20.0×10⁻³ L

Thus, moles of K_2CO_3 :

Moles=0.200 \times {20.0\times 10^{-3}}\ moles

Moles of K_2CO_3 = 0.004 moles

For Ba(NO_3)_2 :

Molarity = 0.400 M

Volume = 30.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume =30.0×10⁻³ L

Thus, moles of Ba(NO_3)_2 :

Moles=0.400\times {30.0\times 10^{-3}}\ moles

Moles of Ba(NO_3)_2  = 0.012 moles

According to the given reaction:

K_2CO_3_{(aq)}+Ba(NO_3)_2_{(aq)}\rightarrow BaCO_3_{(s)}+2KNO_3_{(aq)}

1 mole of potassium carbonate react with 1 mole of barium nitrate

0.004 moles potassium carbonate react with 0.004 mole of barium nitrate

Moles of barium nitrate  = 0.004 moles

Available moles of barium nitrate  =  0.012 moles

Limiting reagent is the one which is present in small amount. Thus, potassium carbonate is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of potassium carbonate gives 1 mole of barium carbonate

Also,

0.004 mole of potassium carbonate gives 0.004 mole of barium carbonate

Mole of barium carbonate = 0.004 moles

Also, consumed barium nitrate = 0.004 moles  (barium ions precipitate with carbonate ions)

Left over moles = 0.012 - 0.004 moles = 0.008 moles

Total volume = 20.0 + 30.0 mL = 50.0 mL = 0.05 L

So, Concentration = 0.008/0.05 M = 0.160 M

<u>(B) is correct.</u>

4 0
3 years ago
POINTS!!!!
Setler79 [48]
C) 3 Moles
This is because of the molecular structure shown in the image

5 0
3 years ago
How many moles are there in 13g of KMnO4?
Hoochie [10]

Answer:

0.08 moles

Explanation:

Relative atomic mass of KMnO4 = K + Mn + O4 = 39 + 55 + 16 x 4 = 158

=> Moles in 13g of KMnO4 = \frac{Mass}{Relative-atomic-mass} = \frac{13}{158} = 0.082278.. = 0.08 moles

3 0
3 years ago
Read 2 more answers
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