Answer:
cancer between 6figures yard is day awl
Micrometer and millimeter
Answer:
HCO₂/H₂O is not the acid-base conjugate pair.
Explanation:
<em>Acid and conjugate base pairs differ by an H+ ion.</em>
Neither HCO₂ nor H₂O has lost or gained protons.
The conjugate acid of H₂O is H₃O⁺
The conjugate base of HCO₃⁻ is CO₃²⁻
[A conjugate acid has one more H⁺ than its base]
Answer:
The estimated feed rate of logs is 14.3 logs/min.
Explanation:
The product of the process is 2000 tons/day of dry wood pulp, of 85 wt% of cellulose. That represents (2000*0.85)=1700 tons/day of cellulose.
That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.
Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.
To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.

The specific gravity of the wood chips is 0.494.
The average volume of a log is

The weight of one log is

To provide 3617 ton/day of wood chips, we need


The feed rate of logs is 14.3 logs/min.
The number of ml of hcl required to react with Zn is calculated as follows
step one: calculate the number of Zn moles
that is mass/ molar mass of Zn
7.65 g/65.38 g /mol= 0.117 moles
step two : write the reacting equation
Zn + 2 HCl ---> ZnCl2 + H2
from the equation above the reacting ratio between ZN to HCl is 1:2
therefore the moles of HCL = 2 x 0.117moles = 0.234 moles
volume of Hcl= moles of HCl / molarity of Hcl
that is 0.234 /6=0.039 L , multiply by 1000 to convert to Ml since molarity is the concentration in litres
0.039 x1000= 39ML