Answer:
Ep= 3.8 10⁵ N/C
Explanation:
Conceptual analysis
The electric field at a point P due to a point charge is calculated as follows:
E = k*q/d²
E: Electric field in N/C
q: charge in Newtons (N)
k: electric constant in N*m²/C²
d: distance from charge q to point P in meters (m)
Equivalence
1nC= 10⁻⁹C
1cm= 10⁻²m
Data
k= 9*10⁹ N*m²/C²
q₁ =+7.5 nC = +7.5*10⁻⁹C
q₂ = -2.0 nC = -2.0*10⁻⁹C
d₁ =d₂ = 1.5cm = 1.5 *10⁻²m = 0.015 m
Calculation of the electric fieldsat the midpoint (P) between the two charges
Look at the attached graphic:
E₁: Electric Field at point ;Due to charge q₁. As the charge q₁ is positive negative (q₁+), the field leaves the charge
.
E₂: Electric Field at point : Due to charge q₂. As the charge q₂ is negative (q₂-) ,the field enters the charge
E₁ = k*q₁/d₁² = 9*10⁹ *7.5 *10⁻⁹/ ( 0.015 )² = 3*10⁵ N/C
E₂ = k*q₂/d₂²= 9*10⁹ *2*10⁻⁹/( 0.015 )² = 0.8*10⁵ N/C
The electric field at a point P due to several point charges is the vector sum of the electric field due to individual charges.
Ep= E₁ + E₂
Ep= 3*10⁵ N/C
+ 0.8*10⁵ N/C
Ep= 3.8 10⁵ N/C
Ok the answer for this question would be B. Hope this helps.
Explanation:
Given that,
A student travels 11 m north and then turns around to travel 25 m south.
Total time, t = 12 s
The total distance or the total path covered by the student is equal to 11 m + 25 m = 36 m
Displacement of the student or the shortest path covered is d = 25-11 = 14 m
(a) The student's average speed = total distance/total time

(b) The student's average velocity = total displacement/total time

Hello!
<span>Let us apply the time function of space, in the uniform uniform motion (UUM)
</span>
Formula:

Data:
S (Final position) = 30 m
So (Initial Position) = 0 m
Vo (Initial velocity) = 0 m/s
t (time) = ? (in seconds)
a (acceleration) = 2.1 m/s²
Solving:










Answer:
<span>
C. 5.3s</span>
I think the correct answer from the choices listed above is option D. Solar cells convert electromagnetic energy into electrical energy. This is because the photons from the rays of light are electromagnetic waves or particles. Hope this answers the question.