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quester [9]
4 years ago
8

the current flowing in an appliance connected to a 120V source is 2A. How many kilowatt-hours of electrical energy does the appl

iance use in 4h
Physics
1 answer:
skad [1K]4 years ago
8 0

Answer:

0.96 kWh

Explanation:

First of all, we can find the power of the appliance using the formula:

P=VI

where

V = 120 V is the voltage of the source

I = 2 A is the current

Substituting,

P(120 V)(2 A)=240 W = 0.24 kW

Now we want to find the amount of energy used by the applied in a time of

t = 4 h

The amount of energy is given by

E=Pt

where

P = 0.24 kW

t = 4 g

Substituting,

E=(0.24 kW)(4 h)=0.96 kWh

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The following table lists the work functions of a few common metals, measured in electron volts. Metal Φ(eV) Cesium 1.9 Potassiu
Citrus2011 [14]

A. Lithium

The equation for the photoelectric effect is:

E=\phi + K

where

E=\frac{hc}{\lambda} is the energy of the incident light, with h being the Planck constant, c being the speed of light, and \lambda being the wavelength

\phi is the work function of the metal (the minimum energy needed to extract one photoelectron from the surface of the metal)

K is the maximum kinetic energy of the photoelectron

In this problem, we have

\lambda=190 nm=1.9\cdot 10^{-7}m, so the energy of the incident light is

E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1.9\cdot 10^{-7} m}=1.05\cdot 10^{-18}J

Converting in electronvolts,

E=\frac{1.05\cdot 10^{-18}J}{1.6\cdot 10^{-19} J/eV}=6.5 eV

Since the electrons are emitted from the surface with a maximum kinetic energy of

K = 4.0 eV

The work function of this metal is

\phi = E-K=6.5 eV-4.0 eV=2.5 eV

So, the metal is Lithium.

B. cesium, potassium, sodium

The wavelength of green light is

\lambda=510 nm=5.1\cdot 10^{-7} m

So its energy is

E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5.1\cdot 10^{-7} m}=3.9\cdot 10^{-19}J

Converting in electronvolts,

E=\frac{3.9\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=2.4 eV

So, all the metals that have work function smaller than this value will be able to emit photoelectrons, so:

Cesium

Potassium

Sodium

C. 4.9 eV

In this case, we have

- Copper work function: \phi = 4.5 eV

- Maximum kinetic energy of the emitted electrons: K = 2.7 eV

So, the energy of the incident light is

E=\phi+K=4.5 eV+2.7 eV=7.2 eV

Then the copper is replaced with sodium, which has work function of

\phi = 2.3 eV

So, if the same light shine on sodium, then the maximum kinetic energy of the emitted electrons will be

K=E-\phi = 7.2 eV-2.3 eV=4.9 eV

7 0
4 years ago
_____ is very corrosive and can cause rusting so metal tanks shouldn't be used
bagirrra123 [75]

Answer:

Iron

Explanation:

5 0
3 years ago
Two charges are separated by a certain distance. If the magnitude of each charge and the distance are both doubled, the force
ycow [4]
Doubled I think i’m not sure tho
3 0
3 years ago
A car speeds past a stationary police officer while traveling 135 km/h. the officer immediately begins pursuit at a constant acc
kykrilka [37]

(a) The time it takes for the police officer to catch up to the speeding car is determined as 0.31 s.

(b) The speed of the police officer  at the time he catches up to the driver is 136.8 km/h.

<h3>Time of motion of the police</h3>

The time taken for the police to catch up with the driver is calculated as follows;

v = at

where;

  • a is acceleration = 11.8 km/h/s, = 3.278 m/s²
  • v is velocity = 135 km/h = 37.5 m/s

t = v/a

t = 37.5/3.278

t = 11.4 seconds

(v1 - v2)t = ¹/₂at² --- (1)

(v1 - v2)t = v1²/2a --- (2)

From (1):

(v1 - 37.5)t = ¹/₂(3.278)t²

(v1 - 37.5)t = 1.639t²

v1 - 37.5 = 1.639t

v1 = 1.639t + 37.5  -----(3)

From (2):

(v1 - 37.5)t = v1²/(2 x 3.278)

(v1 - 37.5)t = 0.153 ----- (4)

solve 3 and 4;

(1.639t + 37.5 - 37.5)t = 0.153

1.639t² = 0.153

t² = 0.0933

t = 0.31 s

<h3>Speed of the police officer</h3>

v1 = 1.639(0.31) + 37.5 = 38 m/s = 136.8 km/h

Learn more about velocity here: brainly.com/question/4931057

#SPJ1

4 0
2 years ago
Diamonds are a very dense material. Predict what would happen to the light ray if you projected it from air through a diamond.
pochemuha
It [the diamond] would act like a prism, and make a rainbow, or, the light would break up and disappear

Hope I helped!
~Mathlete12321

5 0
3 years ago
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