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muminat
3 years ago
10

Is sugar dissolving in water a chemical change

Chemistry
2 answers:
Thepotemich [5.8K]3 years ago
6 0

Answer:

No

Explanation:

Dissolving sugar in water is an example of a physical change.

A chemical change produces new chemical products. In order for sugar in water to be a chemical change, something new would need to result. If you evaporate the water from a sugar-water solution, you're left with sugar.

Alika [10]3 years ago
4 0
No, sugar dissolving in water is a physical change. A chemical change would have changed the whole thing from sugar
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Two substances are combined and react. After 10 minutes, the chemical reaction has reached equilibrium. Which values would be eq
galina1969 [7]

The extra conversion of concentration of reactant and product should be zero in order to attaining equlibrium state.

<h3>What is equilibrium?</h3>

Chemical equilibrium refers to the state in which both the reactants and products are present in equal concentrations or amount. In equlibrium, same amount of reactant is converted into product and product into reactant.

So we can conclude that the extra conversion of concentration of reactant and product should be zero in order to attaining equlibrium state.

Learn more about equilibrium here: brainly.com/question/517289

7 0
2 years ago
How much thermal energy is added to 10.0 g of ice at −20.0°C to convert it to water vapor at 120.0°C?
Sonbull [250]

Answer:

7479 cal.

31262.2 joules

Explanation:

This is a calorimetry problem where water in its three states changes from ice to vapor.

We must use, the calorimetry formula and the formula for latent heat.

Q = m . C . ΔT

Q = Clat . m

First of all, let's determine the heat for ice, before it melts.

10 g . 0.5 cal/g°C ( 0° - (-20°C) = 100 cal

Now, the ice has melted.

Q = Clat heat of fusion . 10 g

Q = 79.7 cal/g . 10 g → 797 cal

We have water  at 0°, so this water has to receive heat until it becomes vapor. Let's determine that heat.

Q = m . C . ΔT

Q = 10 g . 1 cal/g°C (100°C - 0°C) → 1000 cal

Water is ready now, to become vapor so let's determine the heat.

Q = Clat heat of vaporization . m

Q = 539.4 cal/g . 10 g → 5394 cal

Finally we have vapor water, so let's determine the heat gained when this vapor changes the T° from 100°C to 120°

Q = m . C . ΔT

Q = 10 g . 0.470 cal/g°C . (120°C - 100°C) → 94 cal

Now, we have to sum all the heat that was added in all the process.

100 cal + 797 cal + 1000 cal + 5394 cal + 94 cal =7479 cal.

We can convert this unit to joules, which is more acceptable for energy terms.

1 cal is 4.18 Joules.

Then, 7479 cal are (7479 . 4.18) = 31262.2 joules

6 0
3 years ago
Aerobic cellular respiration requires an adequate supply of​
Varvara68 [4.7K]

Answer:

oxygen ?

Explanation:

not sure but I think so

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3 years ago
URGENT
antoniya [11.8K]

Answer:

a

Explanation:

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3 years ago
The smallest unit that can exist as an element and still have the properties of that element is a(n):
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The smallest unit that can exist as an element and still have proprieties of that element is an Atom<span />
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