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2 years ago

HNO3 is arrhenius and increases the concentration of ... when water is added

Chemistry

1 answer:

horsena [70]2 years ago

6 0

It's an Arrhenius acid and increases the concentration of H+ in water and creates H3O+ ions.

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A sample of a substance containing only magnesium and chlorine was tested in the lab and was found to be composed of 74.5% chlor

chubhunter [2.5K]

Use a ratio to find out that x/190.2 = 74.5/100

hope this helps

8 0

2 years ago

¡cual es el % masa/volumen de una mezcla que posee 40 gramos de colorante en 5 litros de mezcla?

Firlakuza [10]

Answer:

what

Explanation:

7 0

3 years ago

The heat of reaction for the combustion of propane is –2,045 kJ. This reaction is: C3H8(g) +502 (g) 3CO2 (g) + 4H2O (g). Determi

Ede4ka [16]

Answer:

$\Delta _fH_{C_3H_8}=-102.7kJ/mol$

Explanation:

Hello,

In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:

$\Delta _cH=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-5*\Delta _fH_{O_2}$

Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:

$\Delta _fH_{C_3H_8}=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-5*\Delta _fH_{O_2}-\Delta _cH\\\\\Delta _fH_{C_3H_8}=3*(-393.5)+4*(-241.8)-5*0-(-2045)\\\\\Delta _fH_{C_3H_8}=-102.7kJ/mol$

Best regards.

8 0

3 years ago

How many grams of KF are in 2 liters of a 3.0 M solution of KF

Rufina [12.5K]

Answer:

mass ( g ) = 348 g

Explanation:

First you know : M = mole / volume (L)

in question you have the M and V and the formula of SUBSTANCE ( KF )

first you get the number of mole from equation above

so 3 = no of mole / 2

no of mole = 3 × 2 = 6 moles

and the moles equation is no of moles = mass ( g ) / molecular weight ( g/mole )

so you have already calculate the moles and you can know the MW from the Question

Mw of KF = 39 + 19 = 58

so n = mass / MW

so 6 = mass / 58

mass ( g ) = 348 g

GOOD LUCK

4 0

3 years ago

Help 20 points !!!!!!!!!!!!!!!!!!!!!!!!!!!! plz do all no scammers

sattari [20]

14 - 2nd one
15 - I do not know
16 - also do not know
Sorry

4 0

3 years ago

Read 2 more answers