Answer:
Speed, 
Explanation:
It is given that,
A light wave is described by the following function as :
![E(x,t)=A\ cos[(1.57\times 10^7)x-(2.93\times 10^{15})t]](https://tex.z-dn.net/?f=E%28x%2Ct%29%3DA%5C%20cos%5B%281.57%5Ctimes%2010%5E7%29x-%282.93%5Ctimes%2010%5E%7B15%7D%29t%5D)
.....(1)
The general equation of wave is given by :
........(2)
On comparing equation (1) and (2)
Wavelength, 
Frequency, 
Let v is the speed of the light wave. It is given by :
So, the speed of the light wave is 
. Hence, this is the required solution.
Explanation:
I think this would help you. Read this and make your own answer ok.
Answer:
The unknown substance is Aluminum.
Explanation:
We'll begin by calculating the change in the temperature of substance. This can be obtained as follow:
Initial temperature (T₁) = 25 ⁰C
Final temperature (T₂) = 100 ⁰C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 100 – 25
ΔT = 75 ⁰C
Finally, we shall determine the specific heat capacity of the substance. This can be obtained as follow:
Change in temperature (ΔT) = 75 ⁰C
Mass of the substance (M) = 135 g
Heat (Q) gained = 9133 J
Specific heat capacity (C) of substance =?
Q = MCΔT
9133 = 135 × C × 75
9133 = 10125 × C
Divide both side by 10125
C = 9133 / 10125
C = 0.902 J/gºC
Thus, the specific heat capacity of substance is 0.902 J/gºC
Comparing the specific heat capacity (i.e 0.902 J/gºC) of substance to those given in the table above, we can see clearly that the unknown substance is aluminum.
To change my friends mind, after they've already said weather predictions are just guesses, I would say they are correct, but not only to they use guesses to predict what will happen, but they also, before hand, use atmospheric tools. They then predict from the data collected. They do both.
1 milliliter = 1 cubic centimeter (cm^3)
