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3 years ago

All planets revolve around the sun counterclockwise,and most also rotate on their axis counterclockwise true or false

1 answer:

8 0

All the planets revolve around the sun counter clockwise and rotate on hteir axis counterclockwise except venus and neptune.

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How is taring accomplished?

attashe74 [19]

Answer:

by taring a balance the process of weighing by difference is done automatically. When a balance is tared with an object, on the balance pan, the weight of the object will be automatically subtracted from reading until the balance is re-tared or zeroed

8 0

3 years ago

Jacob drives his car 7 km east. He stops for lunch, then drives 5 km south before driving 2 km east. What distance did he cover?

Varvara68 [4.7K]

Option (d) is correct.

Distance is the total path length covered by the object.

so, for distance, we add all the path lengths

Here the total distance =7+5+2 =14 km

6 0

3 years ago

A charged particle (Q = 6 C, m = 0.02 kg) moves at a speed of 70 m/s perpendicular to the direction of a uniform magnetic field

san4es73 [151]

Answer:

Explanation:

When a charged particle moves in a magnetic field , a force acts on it perpendicular to its velocity.

Force = Bqv , B is magnetic field , q is charge of the particle and v is velocity

= .03 x 6 x 70

= 12.6 N

5 0

3 years ago

If the station is 40 km away, how long does it take for the radio waves to reach you from the station? Answer in units of second

ddd [48]

Light travels at 300,000km/s. Time of travel is distance/speed. So we have t=40/300000=1.333x10^-4 s.

5 0

3 years ago

.125 kg piece of rubber slows down from 20 m/s to 10m/s as it slides along ice for 102 meters calculate the force of friction

Paha777 [63]

Answer:

-0.18 N

Explanation:

The motion of the piece of rubber is a uniformly accelerated motion, so we can find its acceleration using the suvat equation:

$v^2-u^2=2as$

where:

v = 10 m/s is the final speed

u = 20 m/s is the initial speed

a is the acceleration

s = 102 m is the distance covered

Solving for a,

$a=\frac{v^2-u^2}{2s}=\frac{10^2-20^2}{2(102)}=-1.47 m/s^2$

The net force acting on the piece of rubber is the force of friction; according to Newton's second law of motion, the force is equal to the product of mass (m) and acceleration (a):

$F=ma$

Here we have

m = 0.125 kg is the mass

Therefore, the force of friction is:

$F=ma=(0.125)(-1.47)=-0.18 N$

And the negative sign means the direction of the force is opposite to the direction of motion.

5 0

3 years ago