1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry [639]
3 years ago
14

) you carry a 7.0 kg bag of groceries 1.2 m above the ground at constant velocity across a 2.7 m room. how much work do you do o

n the bag in the process
Physics
1 answer:
lapo4ka [179]3 years ago
3 0
M = 7.0 kg, the mass of the groceries
h = 1.2 m, the elevation of the bag of groceries

The bag of groceries moves a constant velocity over the 2.7-m room.
At constant velocity, there is no applied force, and the kinetic energy remains constant.

At an elevation of 1.2 m, there is an increase in PE (potential energy) given by
V = m*g*h
    = (7.0 kg)*(9.8 m/s²)*(1.2 m)
    = 82.32 J

The change in PE is equal to the work done.

Answer: 82.3 J

You might be interested in
What force is represented by the vector?
choli [55]
Well I think B hope this helps
8 0
2 years ago
Read 2 more answers
I NEED HELP ASAP!!!
alekssr [168]

Answer:

B) 3.6x 10_6 N/C or D)2.8 x105 N/C

7 0
3 years ago
D the element in blue square has a full outer shell, due to it’s location on the periodic table, so it will not react with other
Juliette [100K]
The correct response that will be used to describe this particular element would be the third option, since all of the other options are incorrect and apply to different elements in their groups. The element is a metal and will react with a non metal.






5 0
3 years ago
A steel cable has a cross-sectional area 4.49 × 10^-3 m^2 and is kept under a tension of 2.96 × 10^4 N. The density of steel is
Lemur [1.5K]

Answer:

The transverse wave will travel with a speed of 25.5 m/s along the cable.

Explanation:

let T = 2.96×10^4 N be the tension in in the steel cable, ρ  = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.

then, if V is the volume of the cable:

ρ = m/V

m = ρ×V

but V = A×L , where L is the length of the cable.

m = ρ×(A×L)

m/L = ρ×A

then the speed of the wave in the cable is given by:

v = √(T×L/m)

  = √(T/A×ρ)

  = √[2.96×10^4/(4.49×10^-3×7860)]

  = 25.5 m/s

Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.

7 0
3 years ago
The field-line representation of the e-field in a certain region in space is shown below. The dashed lines represent equipotenti
lorasvet [3.4K]

You need to go on google an dlook this up

3 0
3 years ago
Other questions:
  • A solid disc with a radius of 5.00 m and a mass of 20.0 kg is initially at rests and lies on the plane of the paper. A smaller s
    13·1 answer
  • When a simple magnifying glass is used properly, the image will be formed
    9·1 answer
  • Generalized global air circulation and precipitation patterns are caused by
    13·2 answers
  • Explain why a valve would last longer in the pulmonary position than in the aortic position
    12·1 answer
  • In a day, an electrical resistance heater uses 10 kW-h of electricity. In the same day, the heater delivers 9 kW-h of heat to th
    13·1 answer
  • A particular planet has a moment of inertia of 9.74 × 1037 kg ⋅ m2 and a mass of 5.98 × 1024 kg. Based on these values, what is
    9·1 answer
  • If a large unbalanced force is applied to a stationary low-mass object, what will happen to the object's motion?
    5·1 answer
  • How are the fiducial points of the Celsius and Fahrenheit scales similar?
    14·1 answer
  • Https://brainly.com/question/22600061<br><br> Don’t ask too much science
    14·1 answer
  • The minimum frequency of light needed to eject electrons from a metal is called the threshold frequency, ????0 . Find the minimu
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!