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marysya [2.9K]
3 years ago
13

At 20 Celsius skim milk has a density of 1.033 kilos per liter while light cream has a density of 1.012 kilos per liter. at 20 C

elcius, what is the mass of one gallon of skim milk if 1 liter is approximately 0.264 gallons?
Chemistry
1 answer:
Ahat [919]3 years ago
5 0

Answer:

Mass of 1 gallon skim milk is 3.92 kg.

Explanation:

Density is the ratio of mass to volume.

Density = (mass)/(volume)

0.264 gallons = 1 L

So, 1 gallon = \frac{1}{0.264}L = 3.79 L

So, mass of 3.79 L of skim milk = (density of skim milk)\times(volume of skim milk)

                                                    = (1.033kg/L)\times (3.79L)

                                                    = 3.92 kg

So, mass of 1 gallon skim milk is 3.92 kg.

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ASAP WILL GIVE BRAINLIEST!!
Nataly_w [17]

Answer:

The answer to your question is a) N₂     b) 3.04 g of NH₃

Explanation:

Data

mass of H₂ = 2.5 g

mass of N₂ = 2.5 g

molar mass H₂ = 2.02 g

molar mass of N₂ = 28.02 g

molar mass of NH₃ = 17.04 g

Balanced chemical reaction

                3H₂  +  1 N₂   ⇒   2NH₃

A)

Calculate the theoretical yield 3H₂ / N₂ = 3(2.02) / 28.02 = 0.22

Calculate the experimental yield H₂/N₂ = 2.5/2.5 = 1

Conclusion

The limiting reactant is N₂ (nitrogen) because the experimental proportion was higher than the theoretical proportion.

B)

             28.02 g of N₂ -------------------- (2 x 17.04) g of NH₃

               2.5 g of N₂    --------------------   x

                            x = (2.5 x 2 x 17.04) / 28.02

                            x = 85.2 / 28.02

                           x = 3.04 g of NH₃

6 0
3 years ago
Stochiometry .How many grams of CO2 is produced when excess CS2 reacts with 4 mols of O2? CS2+O2-SO2 Please balance equation.
Travka [436]

Mass of CO₂ produced : 58.67 g

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

CS₂ + 3O₂  -------> CO₂ + 2SO₂

mol of CO₂ based on mol of O₂ as a limiting reactant(CS₂ as an excess reactant)

From the equation, mol ratio of mol CO₂ : mol O₂ = 1 : 3, so mol CO₂  :

\tt \dfrac{1}{3}\times 4=\dfrac{4}{3}

mass  CO₂ (MW= 44 g/mol) :

\tt \dfrac{4}{3}\times 44=58.67~g

4 0
2 years ago
When should you<br> use a fume hood?
AfilCa [17]

Answer:

if you are working with hazardous materials.

Explanation:

A properly operating and correctly used fume hood can reduce or eliminate exposure to volatile liquids, dusts, and mists. It is advisable to use a laboratory hood when working with all hazardous substances.

4 0
3 years ago
A bacteria culture begins with 15 bacteria which double in amount at the end of every hour. Solve for the number of bacteria tha
pshichka [43]
The number of bacteria is given by:
N(t) = N(o) x 2ⁿ
Where N(t) is the number after n hours have passed and N(o) is the original number which is 15.
The number grown in the 12th hour is the difference in the number after the 11th and the 12th hour. Thus:
15 x 2¹² - 15 x 2¹¹
= 30,720 bacteria
5 0
3 years ago
You are given a cube of lead that is 1.000 cm on each side. The density of lead is 11.35. How many atoms of lead are in the samp
aliya0001 [1]

<u>11.35 g</u><u> </u><u>atoms </u><u>of lead are in the sample.</u>

What does density mean?

  • The density of an area refers to the quantity of things—which may include people, animals, plants, or objects—there are in it.
  • Divide the number of objects by the area's measurement to determine density.
  • A country's population density is calculated by dividing its total population by its area, expressed in square kilometers or miles.

We can calculate the volume of the cube by cubing the side of the cube.

Volume of cube = ( 1.000 cm)³

                           = 1.000 cm³

We can now determine the amount of lead in the cube by multiplying by the density. Because we know we have a 1.000 cubic centimeter and that lead has a density of 11.35 grams per cubic centimeter, we have 11.35 grams of lead.

           =  ( 1.000 cm³) ( 11.35 \frac{g}{cm^{3} } )

         = 11.35 g

Learn more about density

brainly.com/question/15164682

#SPJ4

3 0
1 year ago
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