Question

The relationship between the molar concentration of silver ion in a saturated solution of silver phosphate and the solubility product constant for silver phosphate is ________.

Answer 1

Answer: The solubility product of $Ag_3PO_4$ is $27s^4$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

$Ag_3PO_4\leftrightharpoons 3Ag^++PO_4^{3-}$

We are given:

Solubility of $Ag_3PO_4$ = S mol/L

By stoichiometry of the reaction:

1 mole of $Ag_3PO_4$ gives 3 moles of $Ag^{+}$ and 1 mole of $PO_4^{3-}$.

When the solubility of $Ag_3PO_4$  is S moles/liter, then the solubility of $Ag^{+}$ will be 3S moles\liter and solubility of $PO_4^{3-}$ will be S moles/liter.

Expression for the equilibrium constant of $Ag_2CrO_4$ will be:

$K_{sp}=[Ag^+]^3[PO_4^{3-}]$

$K_{sp}=[3s]^3[s]=27s^4$

The solubility product of $Ag_3PO_4$ is $27s^4$