<span>In the Bronsted-Lowry model of acids and bases, a(n) _acid____ is a hydrogen donor and a(n) _base____ is a hydrogen acceptor.</span>
Answer:
Clavulanic acid has two (2) chiral centers.
Explanation:
A chiral center is a center (usually carbon) with four different substituents.
The structure of clavulanic acid is shown in the attachment below.
Consider the labeled diagram in the attachment,
Carbon A is not a chiral carbon because it has two hydrogen atoms attached to it
Carbon B is not a chiral carbon because it has only three substituents
Carbon C is a chiral carbon because it has four different substituents
Carbon D is a chiral carbon because it has four different substituents
Carbon E is not a chiral carbon because it has only three atoms directly attached to it
Carbon F is not a chiral carbon because it has only three atoms directly attached to it
Carbon G is not a chiral carbon because it has two hydrogen atoms attached to it
Carbon H is not a chiral carbon because it has only three substituents
Then, only carbons C and D are chiral carbons.
Hence, clavulanic acid have two (2) chiral centers.
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Mass defect for oxygen-16 = 0. 13261 amu, in the kilograms the mass defect equals to 2.20 × 10⁻²⁸ kg.
<h3>What is mass defect?</h3>
Mass defect is the difference between the mass of of an whole atom and the combined mass of its individual particles present in that atom.
We know that, 1 amu = 1.6 × 10⁻²⁷ kg
Given that, mass defect for oxygen-16 = 0.13261 amu
To calculate this defect in terms of kilograms, we have to convert into kg unit as:
0.13261 amu = 0.13261 amu × 1.6 × 10⁻²⁷ kg/amu
0.13261 amu = 2.20 × 10⁻²⁸ kg
Hence option (2) is correct.
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Answer:
See explanation and image attached
Explanation:
My aim is to convert 1-bromobutane to butanal. The first step is to react the 1-bromobutane substrate with water. This reaction occurs by SN2 mechanism to yield 1-butanol. Hence reagent A is water.
1-butanol is now reacted with an oxidizing agent such as acidified K2Cr2O7 (reagent B) to yield butanal. Note that primary alkanols are oxidized to alkanals.
These sequence of reactions are shown in the image attached.