Molar mass Cu(OH)2 => 97.561 g/mol
Therefore:
1 mole Cu(OH)2 ------------ 97.561 g
? moles Cu(OH)2 ----------- 68 g
= 68 x 1 / 97.561
= 68 / 97.561
= 0.696 moles of Cu(OH)2
F- due to the fact that it has one more electron.
Hope this helps and good luck :)
Answer:
V = 3.1 L
Explanation:
Given data:
Molarity of solution = 0.37 M
Mass of LiF = 29.53 g
Volume of solution = ?
Solution:
Number of moles of LiF:
Number of moles = mass/molar mass
Number of moles = 29.53 g/ 25.94g/mol
Number of moles = 1.14 mol
Volume:
Molarity = number of moles of solute / Volume in L
0.37 M = 1.14 mol / V
V = 1.14 mol / 0.37 M
V = 3.1 L (M = mol/L)
An ionic bond is formed between lithium and bromine.
Explanation:
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