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ololo11 [35]
3 years ago
14

How many nuclear power plants are there in pennsylvania?

Chemistry
1 answer:
wariber [46]3 years ago
7 0
9 I think
bciehbciuedhbciucshbn

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The equilibrium constant for the chemical equation is Kp = 5.23 at 191 °C. Calculate the value of the Kc for the reaction at 191
Lapatulllka [165]
To convert from Kp to Kc, you need this formula---> Kp= Kc (RT)^Δn, where Δn= gas moles of product- gas moles of reactants. since you did not give a reaction formula, I can't calculate Δn. but all once you find it out. just plug it. 

Kp= Kc (RT)^Δn------------------> Kc= Kp/[(RT)^Δn]
 Kp= 5.23
R= 0.0821
T= 191 C= 464 K
Δn= ?

Kc= 5.23/ (0.0821 x 464)^Δn= ???

7 0
3 years ago
Give an example of an unbalanced force.
Margarita [4]
An example is when on a seesaw if a kid is on one side and an adult is on the other then it is unbalanced because the adult weighs more
5 0
3 years ago
Read 2 more answers
What should scentist use after completing a scientific investigation
Zinaida [17]

Answer:

An Educated Guess

Explanation:

After the scientist is done with the experiment he should do an educated guess, they use the data from the experiments to make charts and graphs to communicate the results of the experiment.  After the scientists makes the hypothesis, they perform this procedure.

4 0
2 years ago
Consider the reaction.
Stella [2.4K]

Answer:

when the rates of the forward and reverse reactions are equal

Explanation:

In a chemical system, the reaction reaches a dynamic equilibrium when the rate of formation of product equals the rate of formation of reactants. This implies that both the forward and revered(backwards) reaction are occurring at the same rate.

5 0
3 years ago
Fill in the blanks for the following statements: The rms speed of the molecules in a sample of H2 gas at 300 K will be _________
Anna007 [38]

Answer : The rms speed of the molecules in a sample of H_2 gas at 300 K will be four times larger than the rms speed of O_2 molecules at the same temperature, and the ratio \mu _{rms}(H_2)/\mu _{rms}(O_2) constant with increasing temperature.

Explanation :

Formula used for root mean square speed :

\mu _{rms}=\sqrt{\frac{3RT}{M}}

where,

\mu _{rms} = rms speed of the molecule

R = gas constant

T = temperature

M = molar mass of the gas

At constant temperature, the formula becomes,

\mu _{rms}=\sqrt{\frac{1}{M}}

And the formula for two gases will be,

\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{M_{O_2}}{M_{H_2}}}

Molar mass of O_2 = 32 g/mole

Molar mass of H_2 = 2 g/mole

Now put all the given values in the above formula, we get

\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{32g/mole}{M_{2g/mole}}}=4

Therefore, the rms speed of the molecules in a sample of H_2 gas at 300 K will be four times larger than the rms speed of O_2 molecules at the same temperature.

And the ratio \mu _{rms}(H_2)/\mu _{rms}(O_2) constant with increasing temperature because rms speed depends only on the molar mass of the gases at same temperature.

5 0
3 years ago
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